Question

被修改 我是Spring集成的新手，我正在尝试将数据从服务激活器（通过句柄方法）传递到通道。

public class FileProcessor {

    @ServiceActivator(outputChannel = "xmlChannel")
    public String process(Message<String> msg) {
        String content = msg.getPayload();
        return content;
    }
}

这是FileProcessor类

    public void enrichProduct(Message<String> msg) {
        System.out.println("Enriching product " + msg);
    }
}

这是Enricher课程：公共课Enricher {

public static void main(String[] args) {
    int a[] ={1,2,2,2,2,2,5,5,6,8,9,10};

    System.out.println(5+" first = "+first(a, 5, 0, a.length-1));
    System.out.println(5+" last = "+right(a, 5, 0, a.length-1));

    System.out.println(1+" first = "+first(a, 1, 0, a.length-1));
    System.out.println(1+" last = "+right(a, 1, 0, a.length-1));

    System.out.println(2+" first = "+first(a, 2, 0, a.length-1));
    System.out.println(2+" last = "+right(a, 2, 0, a.length-1));

    System.out.println(10+" first = "+first(a, 10, 0, a.length-1));
    System.out.println(10+" last = "+right(a, 10, 0, a.length-1));

    System.out.println(8+" first = "+first(a, 8, 0, a.length-1));
    System.out.println(8+" last = "+right(a, 8, 0, a.length-1));

    System.out.println(11+" first = "+first(a, 11, 0, a.length-1));
    System.out.println(11+" last = "+right(a, 11, 0, a.length-1));


}

private static int first(int [] a, int x, int l, int h){
    if(l>h){
        return -1;
    }
    int mid = (h-l)/2+l;
    if(a[mid] == x && (mid==0 || a[mid-1] != x) ){
        return mid;
    }else if(a[mid] == x){
        return first(a, x, l, mid-1);
    }else if(a[mid]>x){
        return first(a, x, l, mid-1);
    }else{
        return first(a, x, mid+1, h);
    }
}


private static int right(int [] a, int x, int l, int h){
    if(l>h){
        return -1;
    }
    int mid = (h-l)/2+l;
    if(a[mid] == x && (mid==a.length-1 || a[mid+1] != x) ){
        return mid;
    }else if(a[mid] == x){
        return right(a, x, mid+1, h);
    }else if(a[mid]>x){
        return right(a, x, l, mid-1);
    }else{
        return right(a, x, mid+1, h);
    }
}

Output:
    1 first = 0
    1 last = 0
    2 first = 1
    2 last = 5
    10 first = 11
    10 last = 11
    8 first = 9
    8 last = 9
    11 first = -1
    11 last = -1

消息＆＃34;丰富产品......＆＃34;没有印刷，我不确定出了什么问题。

Answer 1

.channel("xmlChannel")不适合你吗？

这绝对是组成IntegrationFlow的正确方法 - 从消息通道上的一个端点到另一个端点。

我会说outputChannel = "xmlChannel"中的@ServiceActivator只是因为没有inputChannel而无法正常工作。 .handle()以上的内容只会忽略所有这些属性，而只会直接处理fileProcessor.process()方法。

通过.handle（）配置服务激活器的输出通道

1 个答案: