Question

我正在使用此功能创建数月和年份的下拉列表，我的问题是收到如下错误：

'where子句'中的未知列'格式'

下面是任何人帮助摆脱此错误的代码

date_condition = ' and 1=1 ';
if($date_type==1)
{

    $date_condition = ' and m.submittimestamp BETWEEN DATE_SUB(NOW(), INTERVAL 300 DAY) AND NOW() ';
}
else if($date_type==2)
{
    $date_condition = ' and YEAR(m.submittimestamp) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH) and MONTH(m.submittimestamp)=MONTH(CURRENT_DATE - INTERVAL 1 MONTH) ';  
}
else if($date_type==3)
{
    $date_condition = ' and YEAR(m.submittimestamp) = YEAR(date(format)) AND MONTH(m.submittimestamp)=MONTH(date) ';    
}

条件1和2工作正常但条件3正在出错

下面是下拉列表和脚本

<div class="form-group ">
    <input name="filter_options" 
        <?php echo $option3; ?>  
        value="3" onchange="toggleDate(1)" type="radio" class="form-control" id="from_date">
    <label for="from_date">show status for the month of </label>
    <select name="month" class="form-control">
        <?php
        for ($i = 0; $i <= 12; ++$i) {
            $time = strtotime(sprintf('-%d months', $i));
            $value = date('m', $time);
            $label = date('F ', $time);
            printf('<option value="%s">%s</option>', $value, $label);
        }
        ?>
    </select>
    <select name="year" class="form-control">
        <?php
        for ($i = 0; $i <= 12; ++$i) {
            $time = strtotime(sprintf('-%d years', $i));
            $value = date('Y', $time);
            $label = date('Y ', $time);
            printf('<option value="%s">%s</option>', $value, $label);
        }
        ?>
        <option value=" ">year</option>
    </select>
</div>

Answer 1

错误告诉您需要知道的一切，您有语法错误。删除错误中注明的代码开头的字母“e”。

e) AND MONTH(m.submittimestamp)=MONTH(date) GROUP

应该是

) AND MONTH(m.submittimestamp)=MONTH(date) GROUP

创建下拉菜单以查看php中的月份和年份

1 个答案: