Question

我在这条线上遇到错误 this.apiService.getGifs（searchValue.value）.subscribe（数据=＆GT; this.results =数据）;

我的代码有效，但我收到此错误，所以我想弄清楚如何修复它。我认为这部分属于.subscribe(data=>this.results=data);部分，但没有代码就行不通。

apiService

@Injectable()
export class ApiService {

private results = new BehaviorSubject([]);

public getResults$(){
   return this.results.asObservable();
}

  constructor (private http: Http) {}
  link = 'http://api.giphy.com/v1/gifs/search?q=';
  ApiKey = 'MaklOv0qiTVslRvJlBShgpr46LWPs5Z0';

  public getGifs(searchValue:string) {
     return this.http.get(this.link + searchValue +'&api_key='+ this.ApiKey)
     .map((res:Response) => this.results.next(res.json().data));
  }
}

将数据发送到服务的组件

export class SearchComponent implements OnInit {
  results = []

  constructor(private apiService: ApiService) { }

  ngOnInit() {
  }

  onSearch(searchValue) {
   this.apiService.getGifs(searchValue.value).subscribe(data=>this.results=data);
  }
}

接收数据的组件

export class OutputComponent implements OnInit {
  results = [];
    constructor(private apiService: ApiService){
    apiService.getResults$().subscribe(data => this.results = data)
}

Answer 1

除了@jonrsharpe说这应该有效：

 import 'rxjs/add/operator/do';

 public getGifs(searchValue:string) {
     return this.http.get(this.link + searchValue +'&api_key='+ this.ApiKey)
     .map((res:Response) => res.json().data)
     .do( data => this.results.next(data))
  }

键入＆＃39; void＆＃39;不能指定类型＆＃39;任何[]＆＃39;将数据发送到服务时

1 个答案: