如果我通过get请求通过AJAX提取数据，我很好奇如何获取文件的完整URL。
目前，我成功提取的数据包含以下内容：
$('#attachmentIDdetails').html(
'<strong>'+data.attachmentTitle+'</strong><br>Description: '+data.attachmentBody+'<br>Date '+data.attachmentDate +'<br>Type: '+data.attachmentType +'<br>Visibility: '+data.attachmentVisibility + '<br>Uploaded by: '+data.user_id+'<br><a href="'+data.attachmentPath+'">Download Attachment</a><br><img width="100%" src="https://maps.googleapis.com/maps/api/staticmap?center='+data.attachmentLat+',+'+data.attachmentLong+'&zoom=13&scale=1&size=600x300&maptype=roadmap&key=MYSECRETKEY&format=png&visual_refresh=true&markers=size:mid%7Ccolor:0xff0000%7Clabel:%7C'+data.attachmentLat+',+'+data.attachmentLong+'" alt="Google Map of '+data.attachmentLat+',+'+data.attachmentLong+'">' );
}
如果你看，我的一个功能是：data.attachmentPath - 这只是文件名。它位于存储文件夹下的标题为“货件”的文件夹中。那么我将如何提取下载链接的完整URL？
这是我的控制器代码，ajax调用请求：
public function attachmentDetails(Request $request)
{
return Shipment_Attachment::findOrFail($request->attachmentID);
}