Question

我正在尝试从用户输入的下拉菜单中获取输入，并将其提交到我的数据库中的表。我正在尝试将值提交到此表中：我使用POST检查是否从HTML表单中提取了值，但是他们不会提交到我的表中。我确保所有带有列和HTML表单的名称都是正确的，为什么不会将值发布到表中？

<?php

$databaseName = 'pizza_db';
$databaseUser = 'root';
$databasePassword = 'root';
$databaseHost = '127.0.0.1';
$conn = new mysqli($databaseHost, $databaseUser, $databasePassword, $databaseName);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
echo "Connected sucessfully\n";

if(isset($_POST['submit'])){
$value = mysqli_real_escape_string($conn,$_POST['drink']);
$value2 = mysqli_real_escape_string($conn,$_POST['cheese']);
$value3 = mysqli_real_escape_string($conn,$_POST['veggies']);
$value4 = mysqli_real_escape_string($conn,$_POST['meat']);
$value5 = mysqli_real_escape_string($conn,$_POST['sauce']);
$value6 = mysqli_real_escape_string($conn,$_POST['crust']);
$value7 = mysqli_real_escape_string($conn,$_POST['size']);

$sql = "INSERT INTO order_info(drink,cheese,veggies,meat,sauce,crust,size) 
    VALUES('$value','$value2','$value3','$value4','$value5','$value6','$value7')";

//Here I am posting the values to check that they are being submitted 
echo $_POST["size"];
echo "\n";
echo $_POST["sauce"];
echo "\n";
echo $_POST["crust"];
echo "\n";
echo $_POST["cheese"];
echo "\n";
echo $_POST["meat"];
echo "\n";
echo $_POST["veggies"];
echo "\n";
echo $_POST["drink"];
$conn->close();
}
?>

<!DOCTYPE html>
<html>
<body>
<form action='' method='post'>

<p>Choose a size<p>
<select id="size" name="size">
  <option value="small">Small</option>
  <option value="medium">Medium</option>
  <option value="large">Large</option>
  <option value="x-large">X-large</option>
</select>

<p> Choose a sauce <p>
<select id="sauce" name="sauce">
  <option value="none">None</option>
  <option value="marinara">Marinara</option>
  <option value="alfredo">Alfredo</option>
  <option value="ranch">Ranch</option>
  <option value="bbq">BBQ</option>
</select>

<p> Choose a cheese<p>
<select id="cheese" name="cheese">
  <option value="none">None</option>
  <option value="mozzarelaa">Mozarella</option>
  <option value="cheddar">Cheddar</option>
  <option value="parmesan">Parmesan</option>
  <option value="three cheese">Three-Cheese</option>
</select>

<p> Choose a meat <p>
<select id="meat" name="meat">
  <option value="none">None</option>
  <option value="Pepperroni">Pepperroni</option>
  <option value="sausage">Sausage</option>
  <option value="bacon">Bacon</option>
  <option value="canadian bacon">Canadian Bacon</option>
  <option value="chicken">Chicken</option>
  <option value="salami">Beef</option>
  <option value="anchovies">Anchovies</option>
</select>

<p> Choose a veggies <p>
<select id="veggies" name="veggies">
  <option value="none">None</option>
  <option value="onions">Onions</option>
  <option value="green peppers">Green Peppers</option>
  <option value="Red peppers">Red peppers</option>
  <option value="Black olives">Mushrooms</option>
   <option value="jalapenos">Jalapenos</option>
    <option value="tomatoes">Tomatoes</option>
    <option value="pineapple">Pineapple</option>
</select>

<p> Choose a crust <p>
<select id="crust" name="crust">
  <option value="regular">Regular</option>
  <option value="deep-dish">Deep-dish</option>
  <option value="thin-crust">Thin Crust</option>
  <option value="stuffed crust">Stuffed Crust</option>
  <option value="gluten free">Gluten Free</option>
</select>

<p> Choose a drink <p>
<select id="drink" name="drink">
  <option value="none">None</option>
  <option value="rootbeer">Root Beer</option>
  <option value="coke">Coke</option>
  <option value="diet coke">Diet Coke</option>
  <option value="dr pepper">Dr Pepper</option>
</select>
<input type="submit" name="submit" value="Submit"/>
</form>
</body>
</html>

Answer 1

好像你没有运行查询。

// sql
$sql = "INSERT INTO order_info(drink,cheese,veggies,meat,sauce,crust,size) 
VALUES('$value','$value2','$value3','$value4','$value5','$value6','$value7')";

// run query
mysqli_query($conn, $sql);

// or
$conn->query($sql);

Answer 2

您准备了字符串查询，但您没有执行它。

.carousel-item {
    -webkit-backface-visibility: unset!important;
    backface-visibility: unset!important;
}

然后查看你的表格。您将看到保存的数据。

Answer 3

因为操作是空的必须包含表单信息发送到的页面的名称例如：

<form action='page name.php'>
<form action='page name.html'>

如果您要在同一页面上处理此信息，请将包含该表单的页面名称付诸实践

未从PHP HTML表单提交的值

3 个答案: