Question

我有这样一张桌子

+------+----------+------------+
|   id |  1_value |   2_value  |
+------+----------+------------+
|    3 |   foo1   |   other    |
|   10 |   fooX   |   stuff    |
|   13 |   fooJ   |   here     |
|   22 |   foo7   |   and      |
|   31 |   foou   |   here     |
+------+----------+------------+

我想得到的是行号

我试图做这样的事情

SELECT  id, @curRow := @curRow + 1 AS row_number
FROM    table
JOIN    (SELECT @curRow := 0) r

它确实有用......

+------+--------------+
|   id |  row_number  | 
+------+--------------+
|    3 |   1          | 
|   10 |   2          |
|   13 |   3          |
|   22 |   4          |
|   31 |   5          |
+------+--------------+

但如果我尝试选择特定的行怎么办？

SELECT  id, @curRow := @curRow + 1 AS row_number
FROM    srwk_esp_registration
JOIN    (SELECT @curRow := 0) r
WHERE ID = 22

在这种情况下，row_number为1，但应为4。

我怎样才能实现这个目标？

Answer 1

尝试使用子查询：

SELECT * 
FROM (
    SELECT id,
        @curRow := @curRow + 1 AS row_number
    FROM srwk_esp_registration
    JOIN (
        SELECT @curRow := 0
        ) r
    ) sub
WHERE sub.ID = 22

Answer 2

如果您不想声明变量（SET @rownum something）......

通常情况下，我的常规查询是

SELECT t.* FROM ticket t

我会在@i:=@i+1 as row_number,之前或之后添加t.*，并使用(SELECT @i:=0)加入表格：

SELECT @i:=@i+1 as row_number, t.* FROM ticket t, (SELECT @i:=0) AS temp

尝试更改示例查询，希望它有所帮助。

祝你好运！

Mysql获取行号

2 个答案: