我有两个json文件,一个是预期的json,另一个是GET API调用的结果。我需要比较并找出文件中的不匹配。
预计Json:
{
"array": [
1,
2,
3
],
"boolean": true,
"null": null,
"number": 123,
"object": {
"a": "b",
"c": "d",
"e": "f"
},
"string": "Hello World"
}
实际Json回复:
{
"array": [
1,
2,
3
],
"boolean": true,
"null": null,
"number": 456,
"object": {
"a": "b",
"c": "d",
"e": "f"
},
"string": "India"
}
实际上有两个不匹配:收到的数字是456,字符串是印度。
有没有办法比较并将这两个不匹配作为结果。
这需要在gatling / scala中实现。
答案 0 :(得分:0)
例如,您可以使用play-json library并递归遍历两个JSON。对于下一个输入(比你的输入更复杂):
LEFT:
{
"array" : [ 1, 2, 4 ],
"boolean" : true,
"null" : null,
"number" : 123,
"object" : {
"a" : "b",
"c" : "d",
"e" : "f"
},
"string" : "Hello World",
"absent-in-right" : true,
"different-types" : 123
}
RIGHT:
{
"array" : [ 1, 2, 3 ],
"boolean" : true,
"null" : null,
"number" : 456,
"object" : {
"a" : "b",
"c" : "d",
"e" : "ff"
},
"string" : "India",
"absent-in-left" : true,
"different-types" : "YES"
}
它产生这个输出:
Next fields are absent in LEFT:
*\absent-in-left
Next fields are absent in RIGHT:
*\absent-in-right
'*\array\(2)' => 4 != 3
'*\number' => 123 != 456
'*\object\e' => f != ff
'*\string' => Hello World != India
Cannot compare JsNumber and JsString in '*\different-types'
代码:
val left = Json.parse("""{"array":[1,2,4],"boolean":true,"null":null,"number":123,"object":{"a":"b","c":"d","e":"f"},"string":"Hello World","absent-in-right":true,"different-types":123}""").asInstanceOf[JsObject]
val right = Json.parse("""{"array":[1,2,3],"boolean":true,"null":null,"number":456,"object":{"a":"b","c":"d","e":"ff"},"string":"India","absent-in-left":true,"different-types":"YES"}""").asInstanceOf[JsObject]
// '*' - for the root node
showJsDiff(left, right, "*", Seq.empty[String])
def showJsDiff(left: JsValue, right: JsValue, parent: String, path: Seq[String]): Unit = {
val newPath = path :+ parent
if (left.getClass != right.getClass) {
println(s"Cannot compare ${left.getClass.getSimpleName} and ${right.getClass.getSimpleName} " +
s"in '${getPath(newPath)}'")
}
else {
left match {
// Primitive types are pretty easy to handle
case JsNull => logIfNotEqual(JsNull, right.asInstanceOf[JsNull.type], newPath)
case JsBoolean(value) => logIfNotEqual(value, right.asInstanceOf[JsBoolean].value, newPath)
case JsNumber(value) => logIfNotEqual(value, right.asInstanceOf[JsNumber].value, newPath)
case JsString(value) => logIfNotEqual(value, right.asInstanceOf[JsString].value, newPath)
case JsArray(value) =>
// For array we have to call showJsDiff on each element of array
val arr1 = value
val arr2 = right.asInstanceOf[JsArray].value
if (arr1.length != arr2.length) {
println(s"Arrays in '${getPath(newPath)}' have different length. ${arr1.length} != ${arr2.length}")
}
else {
arr1.indices.foreach { idx =>
showJsDiff(arr1(idx), arr2(idx), s"($idx)", newPath)
}
}
case JsObject(value) =>
val leftFields = value.keys.toSeq
val rightJsObject = right.asInstanceOf[JsObject]
val rightFields = rightJsObject.fields.map { case (name, value) => name }
val absentInLeft = rightFields.diff(leftFields)
if (absentInLeft.nonEmpty) {
println("Next fields are absent in LEFT: ")
absentInLeft.foreach { fieldName =>
println(s"\t ${getPath(newPath :+ fieldName)}")
}
}
val absentInRight = leftFields.diff(rightFields)
if (absentInRight.nonEmpty) {
println("Next fields are absent in RIGHT: ")
absentInRight.foreach { fieldName =>
println(s"\t ${getPath(newPath :+ fieldName)}")
}
}
// For common fields we have to call showJsDiff on them
val commonFields = leftFields.intersect(rightFields)
commonFields.foreach { field =>
showJsDiff(value(field), rightJsObject(field), field, newPath)
}
}
}
}
def logIfNotEqual[T](left: T, right: T, path: Seq[String]): Unit = {
if (left != right) {
println(s"'${getPath(path)}' => $left != $right")
}
}
def getPath(path: Seq[String]): String = path.mkString("\\")
答案 1 :(得分:0)
json4s有一个方便的差异函数:https://github.com/json4s/json4s(搜索合并和差异)和API文档:https://static.javadoc.io/org.json4s/json4s-core_2.9.1/3.0.0/org/json4s/Diff.html
答案 2 :(得分:0)
使用diffson - RFC-6901和RFC-6902的Scala实现:https://github.com/gnieh/diffson