Question

list1 = [['WA', 'WA'], ['DC'], ['HI'], ['NJ', 'NJ', 'NJ', 'NJ', 'NJ'], ['TX', 'TX', 'TX'], ['LA', 'LA'], ['NC'], ['NY'], ['IL', 'IL'], ['GA'], ['MA'], ['AZ']]

list2 = [0.875, 10.875, 0, 0, 0, 0, 0.0, 0.0, 10.0, 0, 0, 0, 0.625, -0.25, 0, 10.0, 0.5, 0, 0, 10.0, 9.25]

我希望list3是这样的：

list 3 = [[0.875, 10.875], [0], [0], [0, 0, 0.0, 0.0, 10.0], [0, 0, 0], [0.625, -0.25], [0], [10.0], [0.5, 0], [0], [10.0], [9.25]]

我已经得到了list1的索引：

index_list = [[0, 1], [2], [3], [4, 5, 6, 7, 8], [9, 10, 11], [12, 13], [14], [15], [16, 17], [18], [19], [20]]

Answer 1

以下是使用itertools.accumulate()的解决方案。

from itertools import accumulate

list1 = [['WA', 'WA'], ['DC'], ['HI'], ['NJ', 'NJ', 'NJ', 'NJ', 'NJ'], ['TX', 'TX', 'TX'], ['LA', 'LA'], ['NC'], ['NY'], ['IL', 'IL'], ['GA'], ['MA'], ['AZ']]

list2 = [0.875, 10.875, 0, 0, 0, 0, 0.0, 0.0, 10.0, 0, 0, 0, 0.625, -0.25, 0, 10.0, 0.5, 0, 0, 10.0, 9.25]

# temp to track the starting and ending index positions of the sublists
temp = [0] + list(accumulate(len(x) for x in list1))  
# [0, 2, 3, 4, 9, 12, 14, 15, 16, 18, 19, 20, 21]

list3 = [list2[j:temp[i+1]] for i, j in enumerate(temp[:-1])]  # See 1
# >> [[0.875, 10.875], [0], [0], [0, 0, 0.0, 0.0, 10.0], [0, 0, 0], [0.625, -0.25], [0], [10.0], [0.5, 0], [0], [10.0], [9.25]]

或者，如果您更了解，可以使用list3 = [list2[i:j] for i, j in zip(temp[:-1], temp[1:])]。

Answer 2

直接地：

list1 = [['WA', 'WA'], ['DC'], ['HI'], ['NJ', 'NJ', 'NJ', 'NJ', 'NJ'], ['TX', 'TX', 'TX'], ['LA', 'LA'], ['NC'], ['NY'], ['IL', 'IL'], ['GA'], ['MA'], ['AZ']]
list2 = [0.875, 10.875, 0, 0, 0, 0, 0.0, 0.0, 10.0, 0, 0, 0, 0.625, -0.25, 0, 10.0, 0.5, 0, 0, 10.0, 9.25]

result = []
c = 0
for item in list1:
    item_len = len(item)
    result.append(list2[c: c+item_len])
    c += item_len

print(result)

输出：

[[0.875, 10.875], [0], [0], [0, 0, 0.0, 0.0, 10.0], [0, 0, 0], [0.625, -0.25], [0], [10.0], [0.5, 0], [0], [10.0], [9.25]]

Answer 3

迭代器解决方案如何：

list1 = [['WA', 'WA'], ['DC'], ['HI'], ['NJ', 'NJ', 'NJ', 'NJ', 'NJ'], ['TX', 'TX', 'TX'], ['LA', 'LA'], ['NC'], ['NY'], ['IL', 'IL'], ['GA'], ['MA'], ['AZ']]

list2 = [0.875, 10.875, 0, 0, 0, 0, 0.0, 0.0, 10.0, 0, 0, 0, 0.625, -0.25, 0, 10.0, 0.5, 0, 0, 10.0, 9.25]

f = (x for x in list2)  # iterator

list3 = []
for sub in list1:
  for i, _ in enumerate(sub):
    sub[i] = next(f)  # go fetch me the next element of list2
  list3.append(sub)
print(list3)  # -> [[0.875, 10.875], [0], [0], [0, 0, 0.0, 0.0, 10.0], [0, 0, 0], [0.625, -0.25], [0], [10.0], [0.5, 0], [0], [10.0], [9.25]]**

Answer 4

尝试使用enumerate：

list3 = []
for i,j in enumerate(list1):
    list3.append(list2[i:i+len(j)])

在python中。使用一个列表的格式到另一个列表

4 个答案: