我一直试图在各处找到这个错误，我不知道我搞砸了哪里。我正在编写一个读取文本的程序，将括号推入链接列表堆栈，并在读入匹配的括号时弹出它们。但是，在pop函数中，它会崩溃。
问题在于我的pop（）或我的push（）函数。
OpenSSH_7.2p2 Ubuntu-4ubuntu2.2, OpenSSL 1.0.2g 1 Mar 2016
debug1: Reading configuration data /etc/ssh/ssh_config
debug1: /etc/ssh/ssh_config line 19: Applying options for *
debug1: Connecting to gateway [172.16.24.1] port 22.
debug1: Connection established.
debug1: identity file /home/ops/.ssh/id_rsa type 1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_rsa-cert type -1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_dsa type -1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_dsa-cert type -1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_ecdsa type -1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_ecdsa-cert type -1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_ed25519 type -1
debug1: key_load_public: No such file or directory
debug1: identity file /home/ops/.ssh/id_ed25519-cert type -1
debug1: Enabling compatibility mode for protocol 2.0
debug1: Local version string SSH-2.0-OpenSSH_7.2p2 Ubuntu-4ubuntu2.2
debug1: Remote protocol version 2.0, remote software version OpenSSH_6.6.1p1 Ubuntu-2ubuntu2.7
debug1: match: OpenSSH_6.6.1p1 Ubuntu-2ubuntu2.7 pat OpenSSH_6.6.1* compat 0x04000000
debug1: Authenticating to gateway:22 as 'ops'
debug1: SSH2_MSG_KEXINIT sent
debug1: SSH2_MSG_KEXINIT received
debug1: kex: algorithm: curve25519-sha256@libssh.org
debug1: kex: host key algorithm: ecdsa-sha2-nistp256
debug1: kex: server->client cipher: chacha20-poly1305@openssh.com MAC: <implicit> compression: none
debug1: kex: client->server cipher: chacha20-poly1305@openssh.com MAC: <implicit> compression: none
debug1: expecting SSH2_MSG_KEX_ECDH_REPLY
debug1: Server host key: ecdsa-sha2-nistp256 SHA256:TgaQlbi1L+JBQBbqhJZHIpDnXtJGZtw5y3r2fj7qFAM
debug1: Host 'gateway' is known and matches the ECDSA host key.
debug1: Found key in /home/ops/.ssh/known_hosts:2
debug1: rekey after 134217728 blocks
debug1: SSH2_MSG_NEWKEYS sent
debug1: expecting SSH2_MSG_NEWKEYS
debug1: rekey after 134217728 blocks
debug1: SSH2_MSG_NEWKEYS received
debug1: SSH2_MSG_SERVICE_ACCEPT received
debug1: Authentications that can continue: publickey,password
debug1: Next authentication method: publickey
debug1: Offering RSA public key: /home/ops/.ssh/id_rsa
debug1: Server accepts key: pkalg ssh-rsa blen 535
Enter passphrase for key '/home/ops/.ssh/id_rsa':
以下是驱动程序。
void IntStack::push(int data){
assert(!isFull());
Node *temp = new Node;
temp->data = data;
temp->next = NULL;
}
int IntStack::pop(){
int result = -1;
if(isEmpty()){
result = head->data; //Crashes on this line
Node *temp;
temp = head->next;
delete head;
head = temp;
}
return result;
}
任何帮助将不胜感激。我认为它可能是一个无效的指针..虽然我太缺乏经验，无法告诉。我知道这不是利用堆栈的最有效方式，但它适用于需要使用单链表的类。代码的结尾是不完整的，因为我从未通过我的pop函数。
编辑：其余代码如下。
#include <iostream>
#include <fstream>
#include <string>
#include "IntStack.h"
using namespace std;
bool ArePair(int first,char last){
if(first == '(' && last == ')') return true;
else if(first == '{' && last == '}') return true;
else if(first == '[' && last==']') return true;
return false;
}
int main(){
string fileName;
cout << "Hello, please enter a filename: ";
cin >> fileName;
ifstream inFile;
inFile.open(fileName.c_str());
while (!inFile){
cerr << "ERROR: Cannot open " << fileName << ". Please re-enter.\n";
cin >> fileName;
inFile.open(fileName.c_str());
}
string current;
IntStack iStack;
int par; //parenthesis
while(inFile){
inFile >> current;
for(int i=0;i<current.length();i++){
if(current[i] == '('||current[i] == '{'||current[i] == '['){
par = current[i];
iStack.push(par);
}
else if(current[i] == ')'||current[i] == '}'||current[i] == ']'){
if(!iStack.isEmpty() || !ArePair(par,current[i])){
cout << "debug\n";
}
else{
iStack.pop();
}
}
}
}
inFile.close();
}