获取按匹配的最大列数排列的所有记录

Question

我正在寻找一种方法来获取排列或排序的表中的所有记录，使得匹配的最大列数位于顶部，然后进一步

示例：表名称（车辆）

Id     Name    VehicleMileage    VehicleAverage    VehicleCC    Gear
1    Vehicle1     30HP@2000         25000             1000        3
2    Vehicle2     30HP@2000         22000             8000        2
3    Vehicle3     20HP@2000         21000             5000        4
4    Vehicle4     60HP@2000         25000             1000        3
5    Vehicle5     70HP@2000         23000             3000        3

这里假设搜索到的参数如下：

VehicleMileage: 30HP@2000
VehicleAverage: 25000
VehicleCC: 1000
Gear: 3

查询结果将遵循以下顺序：

Vehicle1 (Reason: 4 matched columns)
Vehicle4 (Reason: 3 matched columns)
Vehicle2 (Reason: 1 matched column)
Vehicle5 (Reason: 1 matched column)
Vehicle3 (No matched column)

我的数据库在SQL服务器上。

Answer 1

尝试这样的事情

SELECT Name + ' (Reason: '+CAST(MatchCount AS VARCHAR)+' matched columns)'
FROM (
        SELECT NAME,(CASE WHEN VehicleMileage ='30HP@2000' THEN 1 ELSE 0 END +
                     CASE WHEN VehicleAverage='25000' THEN 1 ELSE 0 END +
                     CASE WHEN VehicleCC =1000 THEN 1 ELSE 0 END +
                     CASE WHEN Gear =3 THEN 1 ELSE 0 END ) AS MatchCount
       FROM TableName
)t
ORDER BY MatchCount