我正在尝试在我的XCode项目中初始化podfile,以便我可以导入Firebase,但是当我运行pod init
时,我收到以下错误:
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0/bin/pod init
```
你做了什么?
您期望发生什么?
反而发生了什么?
CocoaPods : 1.3.1
Ruby : jruby 9.1.7.0 (2.3.1) 2017-01-11 68056ae Java HotSpot(TM) 64-Bit Server VM 25.92-b14 on 1.8.0_92-b14 +jit [darwin-x86_64]
RubyGems : 2.6.8
Host : Mac OS X 10.11.6 (15G17023)
Xcode : 8.2.1 (8C1002)
Git : git version 2.10.1 (Apple Git-78)
Ruby lib dir : /Users/andrewmcgovern/.rvm/rubies/jruby-9.1.7.0/lib
Repositories : master - https://github.com/CocoaPods/Specs.git @ 18ffe9708184f46d875a2e7e50bddcc085f8d490
cocoapods-deintegrate : 1.0.1
cocoapods-plugins : 1.0.0
cocoapods-search : 1.0.0
cocoapods-stats : 1.0.0
cocoapods-trunk : 1.3.0
cocoapods-try : 1.1.0
NameError - uninitialized constant Nanaimo::Reader::StringScanner
Did you mean? Nanaimo::Reader::StringScanner
StringScanner
org/jruby/RubyModule.java:3344:in `const_missing'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0@global/gems/nanaimo-0.2.3/lib/nanaimo/reader.rb:96:in `initialize'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0@global/gems/xcodeproj-1.5.3/lib/xcodeproj/plist.rb:27:in `read_from_path'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0@global/gems/xcodeproj-1.5.3/lib/xcodeproj/project.rb:200:in `initialize_from_file'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0@global/gems/xcodeproj-1.5.3/lib/xcodeproj/project.rb:102:in `open'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0/gems/cocoapods-1.3.1/lib/cocoapods/command/init.rb:41:in `validate!'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0@global/gems/claide-1.0.2/lib/claide/command.rb:333:in `run'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0/gems/cocoapods-1.3.1/lib/cocoapods/command.rb:52:in `run'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0/gems/cocoapods-1.3.1/bin/pod:55:in `<main>'
org/jruby/RubyKernel.java:979:in `load'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0/bin/pod:1:in `<eval>'
org/jruby/RubyKernel.java:1000:in `eval'
/Users/andrewmcgovern/.rvm/gems/jruby-9.1.7.0/bin/jruby_executable_hooks:15:in `<main>'
如果您对此有回答或了解另一种更好的导入Firebase的方法,请与我们联系。