Question

我有一个像这样格式化的数组（数据）：

＆＃13;

["1", "open_order", "form", "county", "San Diego", "title_officer", "Peter", "0"]
["2", "open_order", "form", "county", "San Diego", "branch", "MV", "0"]

＆＃13;

当我通过for循环并将其添加到dataObject时，console.log（dataObject）为我提供了所有条目（这就是我想要的！）但是，console.log（o）显示最后一个条目进入两个记录的o对象。

＆＃13;

$(function() {
  var o = {};
  var dataObject = {};
  var i = 0;
  var predata = $('#preferences').text();
  var data = JSON.parse(predata);
    for(i = 0; i < data.length; i++) {
      dataObject['preferenceId'] = data[i][0];
      dataObject['pageName'] = data[i][1];
      dataObject['preferenceType'] = data[i][2];
      dataObject['baseField'] = data[i][3];
      dataObject['baseValue'] = data[i][4];
      dataObject['targetField'] = data[i][5];
      dataObject['targetValue'] = data[i][6];
      dataObject['conditionalId'] = data[i][7];
        o[i] = dataObject;
        console.log(dataObject);
    }
  console.log(o);
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

＆＃13;

为什么dataObject对于添加到o对象的所有对象都是一样的想法？

Answer 1

你应该在循环中初始化dataObject以创建一个新变量。

for(i = 0; i < data.length; i++) {
    var dataObject = {}; /* Init the variable here */
    dataObject['preferenceId'] = data[i][0];
    dataObject['pageName'] = data[i][1];
    dataObject['preferenceType'] = data[i][2];
    dataObject['baseField'] = data[i][3];
    dataObject['baseValue'] = data[i][4];
    dataObject['targetField'] = data[i][5];
    dataObject['targetValue'] = data[i][6];
    dataObject['conditionalId'] = data[i][7];
    o[i] = dataObject;
    onsole.log(dataObject);
}

这将导致：

0: {
    baseField: "county",
    baseValue: "San Diego",
    conditionalId: "0",
    pageName: "open_order",
    preferenceId: "1",
    preferenceType: "form",
    targetField: "title_officer",
    targetValue: "Peter"
}
    1: {
    baseField: "county",
    baseValue: "San Diego",
    conditionalId: "0",
    pageName: "open_order",
    preferenceId: "2",
    preferenceType: "form",
    targetField: "branch",
    targetValue: "MV",
}

最终数组上所有值相同的原因是，您只是通过引用分配dataObject，而您没有创建新变量。

用于将对象添加到对象的循环的JavaScript

1 个答案: