Question

var fs = require("fs");
var inquirer = require("inquirer");
var words = ["ALPHA","BRAVO","CHARLIE","DELTA","ECHO","FOXTROT","GOLF","HOTEL","INDIA","JULIET","KILO","LIMA","MIKE","NOVEMBER","OSCAR","PAPA","QUEBEC","ROMEO","SIERRA","TANGO","UNIFORM","VICTOR","WHISKEY","XRAY","YANKEE","ZULU"];

function nodeMan() {
  var wrongs = 0;
  var lettersGuessed = [];
  var word = words[Math.floor(Math.random()*words.length)];
  var goldenBoy = word.split("");
  var blank = "_" * word.length;

  console.log(blank);

  for (var i = 0; wrongs < 10; i++) {
    var neem = "Question " + i;
    inquirer.prompt([{name: neem, message: "Guess a letter"}]).then(function(response) {
      console.log("print");
      lettersGuessed.push(resposne.name);
      if (response.name.length < 1 && lettersGuessed.indexOf(response.name)) {
        console.log(" first if statement cleared");
        for (var u = 0; u < goldenBoy.length; u++) {
          if (goldenBoy[u] === response.name) {
            blank[u] = response.name;
            console.log(blank);
          }
        }
      }
    })
  }
}
nodeMan();

尝试以异步方式运行它。从那时起，我得到一个无限循环的“猜一封信”提示。需要帮助让询问者一次拍摄一个问题而不是无限制。谢谢你的时间！

设置测试文件夹不要忘记npm init和inquirer

Answer 1

你不能使用for循环并且需要使用递归：在你的问题的回答中，你需要决定是否要再问另一个问题并再次发出同样的问题（来自在你的回调中）。

这是一个基本的代码结构，可以帮助您：

function nodeMan() 
  const wrong = 0; // Store the number of wrong answers
  const askQuestion = () => {
    inquirer.prompt([{name: neem, message: "Guess a letter"}]).then((response) => {
      // Here check the answer and decide if you want to ask another question
      // [...]
      wrong++;
      // As long as less than 10 wrong answers, ask the question again
      if (wrong < 10) {
        // Ask the next question
        askQuestion (); // Recursion !
      }
    }
  };                                                                                                                    
}
nodeMan();

Answer 2

如果您要在NodeJS 7.0+下运行代码，可以将函数声明为"async"函数，然后使用"await" operator等待for循环中的异步响应。

var fs = require("fs");
var inquirer = require("inquirer");
var words = ["ALPHA", "BRAVO", "CHARLIE", "DELTA", "ECHO", "FOXTROT", "GOLF", "HOTEL", "INDIA", "JULIET", "KILO", "LIMA", "MIKE", "NOVEMBER", "OSCAR", "PAPA", "QUEBEC", "ROMEO", "SIERRA", "TANGO", "UNIFORM", "VICTOR", "WHISKEY", "XRAY", "YANKEE", "ZULU"];

// declare an async function
async function nodeMan() {
    var wrongs = 0;
    var lettersGuessed = [];
    var word = words[Math.floor(Math.random() * words.length)];
    var goldenBoy = word.split("");
    var blank = "_" + word.length;

    console.log(blank);

    for (var i = 0; wrongs < 10; i++) {
        var neem = "Question " + i;
        // wait for asynchronous response
        var response = await inquirer.prompt([{
            name: neem,
            message: "Guess a letter"
        }]);
        console.log(response)
        console.log("print");
        lettersGuessed.push(response.name);
        if (response.name.length < 1 && lettersGuessed.indexOf(response.name)) {
            console.log(" first if statement cleared");
            for (var u = 0; u < goldenBoy.length; u++) {
                if (goldenBoy[u] === response.name) {
                    blank[u] = response.name;
                    console.log(blank);
                }
            }
        }
    }
}
nodeMan();

如何使用查询器提示异步运行循环

2 个答案: