Question

嘿大家我正在研究数据抓取项目，如果引发异常，我正在寻找一种简洁的方法来重复函数调用。

的伪代码：

try:
    myfunc(x)
except myError:
    ###try to call myfunc(x) again Y number of times, 
        until success(no exceptions raised) otherwise raise myError2

我意识到这根本不是最佳实践，但我正在研究一些不可靠的不同代码/网络层，我无法实际调试它们。

现在我正在通过一系列尝试来完成这项任务\除了积木之外它让我的眼睛流血。

优雅的想法？

Answer 1

为了做到你想要的，你可以做类似以下的事情：

import functools
def try_x_times(x, exceptions_to_catch, exception_to_raise, fn):
    @functools.wraps(fn) #keeps name and docstring of old function
    def new_fn(*args, **kwargs):
        for i in xrange(x):
            try:
                return fn(*args, **kwargs)
            except exceptions_to_catch:
                 pass
        raise exception_to_raise
    return new_fn

然后你只需将旧函数包装在这个新函数中：

#instead of
#risky_method(1,2,'x')
not_so_risky_method = try_x_times(3, (MyError,), myError2, risky_method)
not_so_risky_method(1,2,'x')

#or just
try_x_times(3, (MyError,), myError2, risky_method)(1,2,'x')

Answer 2

使用循环

i = 0
while True:
  try: myfunc(x); break;
  except myError:
    i = i + 1;
    # print "Trying again"
    if i > 5: raise myError2;

Answer 3


for x in xrange(num_retries):
    try:
        myFunc()
    except MyError, err:
        continue
        #time.sleep(1)
    err = None
    break
if err:
    raise MyError2
#else:
#    print "Success!"

Answer 4

我喜欢用递归来解决这些问题：

def tryfor(times, on_failure, excepts, func, *args, **kwargs):
    if times < 1:
        raise on_failure()
    try:
        return func(*args, **kwargs)
    except excepts:
        return tryfor(times-1, on_failure, excepts, func, *args, **kwargs)


tryfor(3, PermanentException, (SomeError,), dostuff,1,2)

Answer 5

在重试之后像往常一样提高异常

from functools import wraps

def retry(times):
    """
    Decorator to retry any functions 'times' times.
    """
    def retry_decorator(func):
        @wraps(func)
        def retried_function(*args, **kwargs):
            for i in range(times - 1):
                try:
                    func(*args, **kwargs)
                    return
                except Exception:  
                    pass
            func(*args, **kwargs)

        return retried_function

    return retry_decorator


# test

attempts = 3

@retry(4)
def function_that_raises_error():
    global attempts
    if 0 < attempts:
        print("fail")
        attempts -= 1
        raise Exception

    print("pass")

function_that_raises_error()

Answer 6

尝试以下代码段：

while True:
    try:
        func()
        break
    except:
        print "Error. Gonna try again"

但最好限制重试次数。

Answer 7

success = False
attempts = 0
while not success and attempts < 10: # or however many times you want to attempt
    try:
        functionCall()
        success = True
    except:
        i += 1
if not success:
    raise functionCallFailedError

希望这有帮助

重复Python函数调用异常？

7 个答案: