Question

我从python中得到了这个错误：

TypeError: list indices must be integers or slices, not list

使用此代码时：

a1, a2, a3, a4, a5, a6, a7, a8, b1, b2, b3, b4, b5, b6, b7, b8 = "a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "b1", "b2", "b3", "b4", "b5", "b6", "b7", "b8", "c1", "c2", "c3", "c4", "c5", "c6", "c7", "c8", "d1", "d2", "d3", "d4", "d5", "d6", "d7", "d8", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "g1", "g2", "g3", "g4", "g5", "g6", "g7", "g8", "h1", "h2", "h3", "h4", "h5", "h6", "h7", "h8" 
bord = [[a1, a2, a3, a4, a5, a6, a7, a8], [b1, b2, b3, b4, b5, b6, b7, b8], [c1, c2, c3, c4, c5, c6, c7, c8], [d1, d2, d3, d4, d5, d6, d7, d8], [e1, e2, e3, e4, e5, e6, e7, e8], [f1, f2, f3, f4, f5, f6, f7, f8], [g1, g2, g3, g4, g5, g6, g7, g8], [h1, h2, h3, h4, h5, h6, h7, h8]]


for y in bord:
    for x in bord[y]:
        print(bord[y][x])

所以我创建了一个8乘8的棋盘（2D列表），其中有象棋的名字。我想为每个单独的方块执行一段代码。

第一个for循环将一次选择1行（因此y为y轴）那么第二个for循环将一次选择1列（因此x为x轴）

对于测试，我刚刚打印了2D列表的位置：

print(bord[y][x])

Answer 1

for y in bord:
    for x in bord[y]:
        print(bord[y][x])

这是错误的，正确的做法是：

for y in bord:
    for x in y:
        print(x)

这是因为for x in arr遍历数组并将元素保存在变量x中，如果您想要执行bord[y][x]的样式，请执行以下操作：

for y in range(len(bord)):
    for x in range(len(bord[y])):
        print(bord[y][x])

此实例中的range()函数从0..len（board） - 1创建一个数组，所以假设bord的大小为5个元素，我们将执行range(5)。这与做for x in [0, 1, 2, 3, 4]相同。因此它迭代该数组并将当前元素保存在变量x中。

所以只是总结一下。

你可以这样做：

for y in bord:
    for x in y:
        print(x)

或

for y in range(len(bord)):
    for x in range(len(bord[y])):
        print(bord[y][x])

您可以使用任何一个，无论您喜欢哪个。使用其中一个可能是有原因但我不知道它，如果有人想编辑它以提供这个原因请做。

希望这有帮助！

list indices必须是整数或切片，而不是来自2D数组python的列表

1 个答案: