Question

我有发送传真的全球api，如下面的代码所示，目前我只能将单个文件作为附件发送传真，但我有另一种情况是在一个传真请求中发送多个文件，文件名按此顺序排列在数据库中可用

以下是发送传真的完整代码

package oracle.apps.print;

import com.softlinx.replixfax.*;
import javax.xml.ws.*;
import org.apache.commons.codec.binary.Base64;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.nio.file.Path;
import java.io.File;

public class Fax {

public String Fax(String Filepath,String faxno,String flg) {

        try {


            ReplixFaxService service = new ReplixFaxService();
            ReplixFaxPort port = service.getReplixFaxPort();
            ((BindingProvider) port).getRequestContext().put(BindingProvider.USERNAME_PROPERTY, "user");
            if (flg.toString().equals("N")) {           
                ((BindingProvider) port).getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,"https://api.rpxfax.com/softlinx/replixfax/wsapi");
        } else {    
                ((BindingProvider) port).getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,"https://api.rpxtest.com:8083/softlinx/replixfax/wsapi");
        }   


            Authentication auth = new Authentication();
            auth.setLogin("user");
            String password="pwd";

            auth.setPassword(org.apache.commons.codec.binary.Base64.encodeBase64String(password.getBytes()));
            auth.setRealm("MTBC");
            auth.setPasswordSecurity("base64");


            SendFaxInput sendFaxInput = new SendFaxInput();
            sendFaxInput.setAuthentication(auth);

            FaxRecipient recipient = new FaxRecipient();
            recipient.setFaxNumber(faxno.toString());

            Attachment attachment = new Attachment();
            File f = new File(Filepath.toString());
            attachment.setFileName(f.getName());

            Path path = Paths.get(Filepath.toString());
            byte[] data = Files.readAllBytes(path);
            attachment.setAttachmentContent(data);

            sendFaxInput.getFaxRecipient().add(recipient);
            sendFaxInput.getAttachment().add(attachment);

        SendFaxOutput result = port.sendFax(sendFaxInput);
            System.out.println("Status Code= " + result.getRequestStatus().getStatusCode());

        if(result.getFaxInfo() != null){
             System.out.println("Fax ID = " + result.getFaxInfo().get(0).getFaxId());

            }
        return result.getRequestStatus().getStatusCode();
    //return "a";



        } catch (Exception ex) {
            System.out.println("Exception: " + ex.getMessage());
        return ex.getMessage();

        }   
    }
 }

我在

附上档案

Attachment attachment = new Attachment();
File f = new File(Filepath.toString());
attachment.setFileName(f.getName());

Path path = Paths.get(Filepath.toString());
byte[] data = Files.readAllBytes(path);
attachment.setAttachmentContent(data);

sendFaxInput.getFaxRecipient().add(recipient);
sendFaxInput.getAttachment().add(attachment);

我可以将我的Above Files字符串解析为多个附件方式，需要帮助将所有文件视为附件

Answer 1

我已经通过自己添加代码来解决这个问题

String[] f_paths = Filepath.split("///");
            for (int i = 0; i < f_paths.length; i++) {

                Attachment attachment = new Attachment();
                File f = new File(f_paths[i].toString());
                attachment.setFileName(f.getName());

                Path path = Paths.get(f_paths[i].toString());
                byte[] data = Files.readAllBytes(path);
                attachment.setAttachmentContent(data);
                sendFaxInput.getAttachment().add(attachment);
            }

只需按分隔符拆分文件字符串，然后通过循环

进行迭代

在单个传真中发送多个文件

1 个答案: