Question

我在使用Angular 4框架的Typescript文件中收到错误。 intelliJ IDE无法识别HttpRequest的任何数据类型。

以下是代码：

import {Component, Injectable, OnInit} from '@angular/core';
import 'rxjs/add/operator/map';
import 'rxjs/add/observable/of';
import { Http, Response } from '@angular/http';
import { Observable } from 'rxjs/Observable';
import 'rxjs/add/operator/map';
import {ActivatedRoute, Router} from "@angular/router";
import {
  HttpClient, HttpErrorResponse, HttpEvent, HttpHandler, HttpHeaders, HttpRequest,
  HttpResponse, HttpInterceptor, HttpEventType} from "@angular/common/http";
import * as $ from "jquery";

@Injectable()
export class Service {

public getNames() {

   intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
       if (request.responseType == 'json') {
       request = request.clone({ responseType: 'text' });

       return next.handle(req).map(response => {
         if (response instanceof HttpResponse) {
         response = response.clone<any>({ body: JSON.parse(response.body) });
      }

      return response;
    });
  }
}

来自以下GitHub网站：https://github.com/angular/angular/issues/18396#issuecomment-349403045

我已经检查过我是否已导入＆＃39; @ angular / common / http＆＃39;并且我的Typescript版本是最新的（我有2.6.2版本）。

有谁知道如何解决这个问题？任何建议都将不胜感激。

谢谢。

Answer 1

使用拦截器的正确方法是：

import {
  Injectable,
} from '@angular/core';
import {
  HttpRequest,
  HttpHandler,
  HttpEvent,
  HttpInterceptor
} from '@angular/common/http';
import {
  Observable
} from 'rxjs/Observable';

@Injectable()
export class MyInterceptor implements HttpInterceptor {
  constructor() {
  }

  intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
    if (request.responseType == 'json') {
      request = request.clone({ responseType: 'text' });
    }

    return next.handle(request).map(// your code here)
  }
}

找到代码中的差异。

Http Interceptor Angular 4

1 个答案: