Question

当我刷新页面内容然后是持久对象时，我有这个错误。

代码处理程序：使用句柄创建表单时的内容函数发布：

  public function post(array $parameters, bool $submitted = false, array $options = [])
        {

            $recruiter = $this->formHandler->handle(
                $this->factory->create(),
                $parameters,
                Request::METHOD_POST,
                $submitted,
                $options
            );
            if ($recruiter instanceof Recruiter) {

            $this->repository->save($recruiter);

            return $recruiter;
        }
    }

代码控制器：使用函数post作为处理程序，我使用try和catch：

/**
         * @Template()
         * @Route("/register", name="register_recruiter")
         *
         * @param Request $request
         *
         * @return array|\Symfony\Component\HttpFoundation\RedirectResponse
         */
        public function registerAction(Request $request)
        {
                  try {


                $quiz = $this->getHandler()->post($request->request->all());



                return $this->redirectToRoute('recruiter_quizs_index');

            } 
            catch (InvalidFormException $e) {
                return [
                    'form' => $e->getForm()->createView(),
                    'edit' => false,
                ];
            }

代码树枝内容形式：

{{ form(form) }}

创建表单的函数句柄：

public function handle($object, array $parameters, string $method, bool $submited = false, array $options = [])
        {
            $options = array_replace_recursive([
                'method' => $method,
                'csrf_protection' => false,
            ], $options);
            $form = $this->formFactory->create(get_class($this->formType), $object, $options);
            if (!$submited) {

                throw new InvalidFormException($form);
            }
            $form->submit($parameters, 'PATCH' !== $method);
            if (!$form->isValid()) {
                throw new InvalidFormException($form);
            }

            return $form->getData();
        }

Answer 1

问题是你没有为第二个参数$submitted提供一个值，如果方法是POST，PUT或PATCH，它应该是true。

解决这个问题的简单方法是检查操作中的方法并提供布尔参数

    /**
     * @Template()
     * @Route("/register", name="register_recruiter")
     *
     * @param Request $request
     *
     * @return array|\Symfony\Component\HttpFoundation\RedirectResponse
     */
    public function registerAction(Request $request)
    {
        try {
            $submitted = ($request->isMethod('PATCH') || $request->isMethod('POST') || $request->isMethod('PUT'));
            $quiz = $this->getHandler()->post($request->request->all(), $submitted);
            return $this->redirectToRoute('recruiter_quizs_index');
        } 
        catch (InvalidFormException $e) {
            return [
                'form' => $e->getForm()->createView(),
                'edit' => false,
            ];
        }

虽然我认为这是一个非常糟糕的解决方案。您应该为每个HTTP方法创建一个操作。使用GET显示表单，使用POST / PUT / PATCH提交。将提交路由放在GET路由之前，因此它将首先匹配：

    /**
     * submit the recruiter form (on PATH, POST, PUT)
     *
     * @Template()
     * @Route("/register", name="register_recruiter_submit", methods={"PATCH","POST","PUT"})
     *
     * @param Request $request
     *
     * @return array|\Symfony\Component\HttpFoundation\RedirectResponse
     */
    public function registerSubmitAction(Request $request)
    {
        try {
            $quiz = $this->getHandler()->post($request->request->all(), true);
            return $this->redirectToRoute('recruiter_quizs_index');
        } 
        catch (InvalidFormException $e) {
            return [
                'form' => $e->getForm()->createView(),
                'edit' => false,
            ];
        }
    }

    /**
     * show the recruiter form (route will match if method is not PATCH/PUT/POST
     *
     * @Template()
     * @Route("/register", name="register_recruiter_form")
     *
     * @param Request $request
     *
     * @return array|\Symfony\Component\HttpFoundation\RedirectResponse
     */
    public function registerFormAction(Request $request)
    {
        return [
            'form' => $this->formHandler->createView(),
            'edit' => false,
        ];
    }

提交的数据无效

1 个答案: