Question

为了编写一些干净整洁的JavaScript，我正在尝试使用Modules。我创建了这个规则模块：

//RulesModule.js
var RulesModule = (function () {

    return {

        checkModal: function () {
            var checkModalContents = // string contents

            return checkModalContents;
        },

        ruleModals: function (modalType) {
            switch (modalType) {
                case "CheckDateRule":
                    return checkModal();
                default:
                    return "UNKNOWN MODAL";
            }
        }
    }
});

然后我挂钩到下拉元素的事件，当选择一个选项时，我们将该选项传递给RulesModule.ruleModals方法，以获得正确的模态。

//EventSubscriptions.js
    var go = false;//switch off
    $('#rules').on('click', function () {//on click
    if (go) {//if go
            var selectedRule = $("#rules").find(":selected").val();

            var contents = RulesModule.ruleModals(selectedRule); // this line throws the error

            console.log(contents);
            $("#modalContents").empty(); // clear up contents
            $("#modalContents").append(contents);
            $("#myModal").css("display", "block");

        go = false;//switch off
    } else { go = true; }//if !go, switch on
}).on('blur', function () { go = false; });//switch off on blur

在我的HTML中，我在标题中加载了两个javascript文件：

<head>
   <meta charset="utf-8" />
   <title></title>
   <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
   <script src="~/JavaScript/Modules/RulesModule.js"></script>
   <script src="~/JavaScript/EventSubscriptions.js"></script>
</head>

Answer 1

RulesModule的回复是一个对象checkModal＆amp; ruleModals是两种方法，因此请尝试按checkModal

调用this.checkModal

＆＃13;

var RulesModule = (function() {
  return {
    checkModal: function() {
      var checkModalContents = ''; // string contents
      console.log('Check Modal called')
      return checkModalContents;
    },
    ruleModals: function(modalType) {
      switch (modalType) {
        case "CheckDateRule":
          return this.checkModal();
        default:
          return "UNKNOWN MODAL";
      }
    }
  }
}());

console.log(RulesModule.ruleModals('CheckDateRule'))

＆＃13;

获取未捕获的TypeError：RulesModule.ruleModals不是函数

1 个答案: