我有以下表格(下表是简化更复杂的任务):
abc.FirstTable
ID | Name
---------
10 | test
abc.SecondTable
Id | RefId
----------
20 | 10
21 | 10
我想要的是:
Id | Name | RefId1 | RefId2
---------------------------
10 | test | 20 | 21
我坚持:
select t1.id, t1.name, t2.ID from abc.FirstTable t1
left join abc.SecondTable t2 on t2.refid = t1.id;
产生两行。有关如何使用连接扩展此查询的任何提示?谢谢!
答案 0 :(得分:1)
with t as
(
select t1.id id1, t1.name, t2.* from abc_FirstTable t1 join abc_SecondTable t2 on t2.refid = t1.id
)
select * from t
pivot
(
min(id) min_id, max(id) max_id
for (refid) in (10)
);