Question

我试图将一些时间戳（字符）转换为POSIXct对象：

> u <- "December 05, 2017 1:00 PM"

我使用as.POSIXct如下：

> as.POSIXct(u, format = "%B %d, %Y %H:%M %p", tz = "UTC")
[1] "2017-12-05 01:00:00 UTC"

我希望输出显示小时13而不是01：

"2017-12-05 13:00:00 UTC"

我已经看到这里发布的问题：Parse timestamp with a.m./p.m但我似乎有正确的输入和格式字符串（%p）。

as.POSIXct似乎完全忽略字符串的AM / PM部分，因此AM时间戳工作正常，但PM戳记滞后12小时。以下是一些数据来说明这一点：

> sample_tstamps
 [1] "December 05, 2017 8:00 AM"  "December 05, 2017 9:00 AM"  "December 05, 2017 10:00 AM" "December 05, 2017 11:00 AM"
 [5] "December 05, 2017 12:00 PM" "December 05, 2017 1:00 PM"  "December 05, 2017 2:00 PM"  "December 05, 2017 3:00 PM" 
 [9] "December 05, 2017 4:00 PM"  "December 05, 2017 5:00 PM" 
> as.POSIXct(sample_tstamps, format = "%B %d, %Y %H:%M %p", tz = "UTC")
 [1] "2017-12-05 08:00:00 UTC" "2017-12-05 09:00:00 UTC" "2017-12-05 10:00:00 UTC" "2017-12-05 11:00:00 UTC"
 [5] "2017-12-05 12:00:00 UTC" "2017-12-05 01:00:00 UTC" "2017-12-05 02:00:00 UTC" "2017-12-05 03:00:00 UTC"
 [9] "2017-12-05 04:00:00 UTC" "2017-12-05 05:00:00 UTC"

Answer 1

使用R-package lubridate：

u <- "December 05, 2017 1:00 PM"
lubridate::mdy_hm(u)
#[1] "2017-12-05 13:00:00 UTC"

Answer 2

我们需要%I而不是%H

as.POSIXct(u, format = "%B %d, %Y %I:%M %p", tz = "UTC")
#[1] "2017-12-05 13:00:00 UTC"

解析时间戳 - AM / PM无法识别

2 个答案: