Question

每当我点击<tr>按钮时，我想复制现有+的情况：<i class="fa fa-plus" aria-hidden="true"></i>

以下是我的<tr>。如何使用jquery或javascript

生成它

 <tr>
    <td>
        <div class="row noPadding vendorForm">
            <div class="vendorDaterow">
                <div class="vendorName">
                    <label>SP Vender Name</label><span>Shri Kamalkanth Co.</span>
                </div>
                <div class="vendorFromDate">
                    <label>From Date</label><span class="datepicker"><input type="text" id="spFromDate1" /><i class="fa fa-calendar" aria-hidden="true"></i></span>
                </div>
                <div class="vendorToDate">
                    <label>To Date</label><span class="datepicker"><input type="text" id="spToDate1" /><i class="fa fa-calendar" aria-hidden="true"></i></span>
                </div>
            </div>
            <div class="add">
                <i class="fa fa-plus" aria-hidden="true"></i>
            </div>
            <i class="max">(Maximum 5 Vendors)</i>

        </div>
    </td>
</tr>

Answer 1

您首先 clone() 通过 closest() 找到父<tr/> 并将其作为兄弟插入通过 insertAfter() 。确保还将true作为参数传递，以便所有后代与其事件和数据一起传递。

$('.add').on('click', function() {
  var $tr = $(this).closest('tr');

  $tr.clone(true, true).insertAfter($tr)
});

Answer 2

您可以使用此

(function () {
  var toAddCloneCount = 2;

$('.add').on('click', function() {
  var $tr = $(this).closest('tr');
  var $tr2 = $tr.clone(true, true);
  $tr2.find(".vendorName").children('label').remove();
  $tr2.find(".add").children().remove();
  $tr2.find(".vendorFromDate").children('label').remove();
  $tr2.find(".vendorToDate").children('label').remove();
  $tr2.find('#txtVendorName').prop('id', 'txtVendorName' + toAddCloneCount);
  $tr2.find('#spFromDate1').prop('id', 'spFromDate' + toAddCloneCount);
  $tr2.find('#spToDate1').prop('id', 'spToDate' + toAddCloneCount++);
  $tr2.insertAfter($tr);
});
})();

.vendorName,.vendorFromDate,.vendorToDate{
width:33%;float:left;}

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/font-awesome/4.7.0/css/font-awesome.min.css"/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
                            <td>
                                <div class="row noPadding vendorForm">
                                    <div class="vendorDaterow">
                                        <div class="vendorName">
                                            <label>SP Vender Name</label><span>@*Shri Kamalkanth Co.*@<input type="text" name="nmVendorData" id="txtVendorName" /></span> 
                                        </div>
                                        <div class="vendorFromDate">
                                            <label>From Date</label><span class="datepicker"><input type="text" id="spFromDate1" /><i class="fa fa-calendar" aria-hidden="true"></i></span>
                                        </div>
                                        <div class="vendorToDate">
                                            <label>To Date</label><span class="datepicker"><input type="text" id="spToDate1" /><i class="fa fa-calendar" aria-hidden="true"></i></span>
                                        </div>
                                    </div>
                                    <div class="add">
                                        <i class="fa fa-plus" aria-hidden="true"></i>
                                    </div>
                                    <i class="max">(Maximum 5 Vendors)</i>

                                </div>
                            </td>
                        </tr>
</table>

Answer 3

使用clone()和after()：

$(document).ready(function(){
    $("i.fa-plus").click(function(){
        var val = $("tr:last").clone()
        $("tr:last").after(val)
    });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
    <td>
        <div class="row noPadding vendorForm">
            <div class="vendorDaterow">
                <div class="vendorName">
                    <label>SP Vender Name</label><span>Shri Kamalkanth Co.</span>
                </div>
                <div class="vendorFromDate">
                    <label>From Date</label><span class="datepicker"><input type="text" id="spFromDate1" /><i class="fa fa-calendar" aria-hidden="true"></i></span>
                </div>
                <div class="vendorToDate">
                    <label>To Date</label><span class="datepicker"><input type="text" id="spToDate1" /><i class="fa fa-calendar" aria-hidden="true"></i></span>
                </div>
            </div>

        </div>
    </td>
</tr>
 </table>
            <div class="add">
                <i class="fa fa-plus" aria-hidden="true">+</i>
            </div>
            <i class="max">(Maximum 5 Vendors)</i>

Answer 4

您需要某种方式<tr>的模板。使用某种模板引擎或懒惰方式：在页面加载时复制它。（复制<tr>时没有现有输入）

var $template = $('yourTrSelector').clone();

然后将其粘贴在按钮上。

$('yourButtonSelector').on('click', function(){
  $('yourTableSelector').append($template.copy());
});

单击图像按钮jquery生成tr

4 个答案: