我阅读了几篇关于类似问题的帖子，似乎无法找到正确的解决方案。我已经尝试将计算添加到查询的几个部分，但没有成功。我确信我错过了一些简单的事情。
我在矿场工作，我被要求完成以下任务：
他们想知道哪些卡车在过去3天内比所有其他卡车平均有效载荷的平均有效载荷低5％以上。它还需要排除任何载荷小于10的卡车
共有3个表格：
hist_loads（提供有效载荷和许多其他信息）
hist_exproot（提供与日期相关的信息，需要这样做
hist_eqmtlist（需要这个来确定具体的卡车型号，如 并非所有卡车车型都必须包括在内）
所有上述表格都由一个名为“shiftindex”的列连接在一起
以下是我的查询：
IF OBJECT_ID ('tempdb.dbo.#pave') IS NOT NULL DROP TABLE dbo.#pave;
IF OBJECT_ID ('tempdb.dbo.#pfinal') IS NOT NULL DROP TABLE dbo.#pfinal;
select
shiftdate
,truck
,AVG(measureton) as measureton
,COUNT(excav) as loads
into #pfinal
from hist_loads as hl
inner join hist_exproot as he on
he.shiftindex = hl.shiftindex
inner join hist_eqmtlist as heq on
heq.shiftindex = hl.shiftindex and
hl.truck = heq.eqmtid
where hl.shiftindex between
(select min(shiftindex)
from hist_exproot
where datepart(year,shiftdate) = datepart(year, getdate()-3)
and datepart(month,shiftdate) = datepart(month, getdate()-3)
and datepart(day,shiftdate) = datepart(day, getdate()-3))
and
(select max(shiftindex)
from hist_exproot
where datepart(year,shiftdate) = datepart(year, getdate()-1)
and datepart(month,shiftdate) = datepart(month, getdate()-1)
and datepart(day,shiftdate) = datepart(day, getdate()-1))
and eqmttype in ('Euclid EH4500','Euclid EH4500-W','Euclid EH4500-HW')
and expit like 1
and measureton not like 0
group by eqmttype, truck, shiftdate
having COUNT(excav) > 10
select
shiftdate
,AVG(measureton) as measureton
,COUNT(excav) as loads
into #pave
from hist_loads as hl
inner join hist_exproot as he on
he.shiftindex = hl.shiftindex
inner join hist_eqmtlist as heq on
heq.shiftindex = hl.shiftindex and
hl.truck = heq.eqmtid
where hl.shiftindex between
(select min(shiftindex)
from hist_exproot
where datepart(year,shiftdate) = datepart(year, getdate()-3)
and datepart(month,shiftdate) = datepart(month, getdate()-3)
and datepart(day,shiftdate) = datepart(day, getdate()-3))
and
(select max(shiftindex)
from hist_exproot
where datepart(year,shiftdate) = datepart(year, getdate()-1)
and datepart(month,shiftdate) = datepart(month, getdate()-1)
and datepart(day,shiftdate) = datepart(day, getdate()-1))
and eqmttype in ('Euclid EH4500','Euclid EH4500-W','Euclid EH4500-HW')
and measureton not like 0
group by eqmttype, shiftdate
having COUNT(excav) > 10
select ave.shiftdate, ave.measureton, final.truck
from #pave as ave
left join #pfinal as final on
ave.shiftdate = final.shiftdate
where final.measureton < ave.measureton
order by truck
我的结果：
shiftdate measureton truck
2017-12-03 00:00:00 230.444365964912 DT01
2017-12-02 00:00:00 231.123014419048 DT04
2017-12-02 00:00:00 231.123014419048 DT07
2017-12-03 00:00:00 230.444365964912 DT07
2017-12-04 00:00:00 226.141955641026 DT07
2017-12-04 00:00:00 226.141955641026 DT10
2017-12-02 00:00:00 231.123014419048 DT13
2017-12-03 00:00:00 230.444365964912 DT14
2017-12-02 00:00:00 231.123014419048 DT15
2017-12-03 00:00:00 230.444365964912 DT17
2017-12-04 00:00:00 226.141955641026 DT17
2017-12-03 00:00:00 230.444365964912 DT20
2017-12-04 00:00:00 226.141955641026 DT20
2017-12-02 00:00:00 231.123014419048 DT22
2017-12-04 00:00:00 226.141955641026 DT24
2017-12-02 00:00:00 231.123014419048 DT25
2017-12-02 00:00:00 231.123014419048 DT27
2017-12-03 00:00:00 230.444365964912 DT27
2017-12-04 00:00:00 226.141955641026 DT28
2017-12-02 00:00:00 231.123014419048 DT30
2017-12-02 00:00:00 231.123014419048 DT31
2017-12-03 00:00:00 230.444365964912 DT31
2017-12-04 00:00:00 226.141955641026 DT32
但我只需要平均有效载荷以下5％以上的卡车。上述结果似乎是过去3天内所有卡车的平均有效载荷。而且在3个数字之间似乎也有一些重复。
任何帮助都将不胜感激。
答案 0 :(得分：0)
如果没有可测试且可验证的示例，很难回答，但我设法做到了：
0 info it worked if it ends with ok
1 verbose cli [ 'C:\\Program Files\\nodejs\\node.exe',
1 verbose cli 'C:\\Program Files\\nodejs\\node_modules\\npm\\bin\\npm-cli.js',
1 verbose cli 'run',
1 verbose cli 'coverage' ]
2 info using npm@5.3.0
3 info using node@v6.4.0
4 verbose run-script [ 'precoverage', 'coverage', 'postcoverage' ]
5 info lifecycle gulp-karma@1.0.0~precoverage: gulp-karma@1.0.0
6 info lifecycle gulp-karma@1.0.0~coverage: gulp-karma@1.0.0
7 verbose lifecycle gulp-karma@1.0.0~coverage: unsafe-perm in lifecycle true
8 verbose lifecycle gulp-karma@1.0.0~coverage:
9 verbose lifecycle gulp-karma@1.0.0~coverage: CWD: D:\workspace\TestGroup\viewer
10 silly lifecycle gulp-karma@1.0.0~coverage: Args: [ '/d /s /c',
10 silly lifecycle 'concurrently "gulp common" "gulp feature" "gulp file" "gulp layout" "gulp widget_zero" "gulp widget_one" "gulp mobile_common" "gulp mobile_feature" "gulp mobile_file" "gulp mobile_layout" "gulp mobile_widget"' ]
11 silly lifecycle gulp-karma@1.0.0~coverage: Returned: code: 1 signal: null
12 info lifecycle gulp-karma@1.0.0~coverage: Failed to exec coverage script
13 verbose stack Error: gulp-karma@1.0.0 coverage: `concurrently "gulp common" "gulp feature" "gulp file" "gulp layout" "gulp widget_zero" "gulp widget_one" "gulp mobile_common" "gulp mobile_feature" "gulp mobile_file" "gulp mobile_layout" "gulp mobile_widget"`
13 verbose stack Exit status 1
13 verbose stack at EventEmitter.<anonymous> (C:\Program Files\nodejs\node_modules\npm\lib\utils\lifecycle.js:289:16)
13 verbose stack at emitTwo (events.js:125:13)
13 verbose stack at EventEmitter.emit (events.js:213:7)
13 verbose stack at ChildProcess.<anonymous> (C:\Program Files\nodejs\node_modules\npm\lib\utils\spawn.js:40:14)
13 verbose stack at emitTwo (events.js:125:13)
13 verbose stack at ChildProcess.emit (events.js:213:7)
13 verbose stack at maybeClose (internal/child_process.js:927:16)
13 verbose stack at Process.ChildProcess._handle.onexit (internal/child_process.js:211:5)
14 verbose pkgid gulp-karma@1.0.0
15 verbose cwd D:\workspace\TestGroup\viewer
16 verbose Windows_NT 10.0.14393
17 verbose argv "C:\\Program Files\\nodejs\\node.exe" "C:\\Program Files\\nodejs\\node_modules\\npm\\bin\\npm-cli.js" "run" "coverage"
18 verbose node v6.4.0
19 verbose npm v5.3.0
20 error code ELIFECYCLE
21 error errno 1
22 error gulp-karma@1.0.0 coverage: `concurrently "gulp common" "gulp feature" "gulp file
这是获得平均值并将其存储在where子句中使用的变量的简单案例。
答案 1 :(得分：0)
看起来你非常接近......没有你的实际数据就无法确认，但让我们看看这个简化的查询是否适合你......
第一个查询，我已经预先计算出只收集基于日期字段的数据，而不必单独分解年/月/日。
GetDate（）本身将返回当前日期和时间。为了得到日期，我正在运行CONVERT（date，getdate（）），所以2017-12-05 08:22:15 am被剥夺到2017-12-05。此外，通过做dateadd（）-3天将把这个降低到2017-12-02。 where子句现在＆gt; ='2017-12-02'并且比'2017-12-05'少，包括'2017-12-04 at 11:59:59 pm'获得整个12-04天覆盖了您要求的整个3天。
你最初的计数＆gt; 10但据说要丢弃任何少于10次旅行的人，所以我改为＆gt; = 10.你的其他标准保持原样。
因此，在对临时表的第一次查询结束时，仅为符合条件的卡车提供3天的活动，并获得每辆卡车的平均值。
SELECT
shiftdate,
truck,
AVG(measureton) as measureton,
COUNT(excav) as loads
into
#pTruckAvgs
from
hist_loads as hl
inner join hist_exproot as he
ON hl.shiftindex = he.shiftindex
inner join hist_eqmtlist as heq
ON hl.shiftindex = heq.shiftindex
and hl.truck = heq.eqmtid
where
hl.shiftindex >= DateAdd( day, -3, CONVERT(date, getdate()) )
and hl.shiftindex < CONVERT(date, getdate())
and eqmttype in ('Euclid EH4500','Euclid EH4500-W','Euclid EH4500-HW')
and expit like 1
and measureton not like 0
group by
eqmttype,
truck,
shiftdate
having
COUNT(excav) >= 10;
现在，您有一张所有卡车的临时表及其各自的平均值。您不需要根据日期再次重新查询，只需从此临时表中获取平均值（通过QualAvgs结果别名）。在这里，你寻找比平均值低5％，所以我采取平均值* .95并得到所有卡车平均值低于所有平均值的95％。完成后删除临时表。
select
TA.*,
QualAvgs.AllAvg
from
#pTruckAvgs TA,
( select AVG(measureton) as AllAvg
from #pTruckAvgs ) QualAvgs
where
TA.measureTon < ( QualAvgs.AllAvg * .95);
drop table #pTruckAvgs;
现在最后的想法...对于每天的平均值可能需要稍微改变......例如，如果恶劣的天气或其他不可预见的限制使每辆卡车在一天内变慢，您可能需要
select
TA.*,
QualAvgs.AllAvg
from
#pTruckAvgs TA,
( select shiftdate,
AVG(measureton) as AllAvg
from #pTruckAvgs
group by shiftdate ) QualAvgs
where
TA.measureTon < ( QualAvgs.AllAvg * .95)
AND TA.ShiftDate = QualAvgs.ShiftDate;
答案 2 :(得分：0)
@DRapp。谢谢，这有点工作，有点调整。您的日期逻辑在SSMS中给了我一些错误。所以我用我的日期逻辑替换它：
Msg 206, Level 16, State 2, Line 1
Operand type clash: date is incompatible with int
我还在select语句中删除了shiftdate，因为我意识到不需要将它拆分成单独的日期。根据要求，我还将时间范围延长至7天。所以最终的工作查询如下：
IF OBJECT_ID ('tempdb.dbo.#pTruckAvgs') IS NOT NULL DROP TABLE dbo.#pTruckAvgs;
SELECT
truck,
AVG(measureton) as measureton,
COUNT(excav) as loads
into
#pTruckAvgs
from
hist_loads as hl
inner join hist_exproot as he
ON hl.shiftindex = he.shiftindex
inner join hist_eqmtlist as heq
ON hl.shiftindex = heq.shiftindex
and hl.truck = heq.eqmtid
where
hl.shiftindex between
(select min(shiftindex)
from hist_exproot
where datepart(year,shiftdate) = datepart(year, getdate()-7)
and datepart(month,shiftdate) = datepart(month, getdate()-7)
and datepart(day,shiftdate) = datepart(day, getdate()-7))
and
(select max(shiftindex)
from hist_exproot
where datepart(year,shiftdate) = datepart(year, getdate()-1)
and datepart(month,shiftdate) = datepart(month, getdate()-1)
and datepart(day,shiftdate) = datepart(day, getdate()-1))
--and hl.shiftindex < CONVERT(date, getdate())
and eqmttype in ('Euclid EH4500','Euclid EH4500-W','Euclid EH4500-HW')
and expit like 1
and measureton not like 0
and measureton > 150
group by
eqmttype,
truck
having
COUNT(excav) >= 10;
select
TA.*,
QualAvgs.AllAvg
from
#pTruckAvgs TA,
(select AVG(measureton) as AllAvg
from #pTruckAvgs ) QualAvgs
where
TA.measureTon < ( QualAvgs.AllAvg * .95);
结果如下：
truck measureton loads AllAvg
DT05 204.876060232558 43 224.850465129605
感谢大家的帮助，我们非常感谢。