Question

我想将两个PHP数组合并到第三个数组，我希望将它们依赖于相同的键data。我在两个数组中都有data个密钥，我想留下来。我想要依赖First array。我的意思是我将第一个数组加载到final_array()，接下来我将第三个密钥从第二个ESTYMACJA添加为array，但是从已加载的data密钥添加到同一个data final_array()。如果data中没有final_array()个密钥，则算法应将此密钥添加到final_array()，添加WYKONANIA并复制ESTYMACJA。如果可能的话，我也会将ESTYMACJA复制到其余的data个密钥中。我会在final_array()期望中表明我的意思。

第一阵列：

$my_array=[
    ['data'=>'2017-11-27','ESTYMACJA'=>5000],
    ['data'=>'2017-11-30','ESTYMACJA'=>9000]
];

第二阵列：

$new_array=[
    ['data'=>'2017-11-01','WYKONANIA'=>3],
    ['data'=>'2017-11-02','WYKONANIA'=>10],
    ['data'=>'2017-11-03','WYKONANIA'=>303],
    ['data'=>'2017-11-04','WYKONANIA'=>327],
    ['data'=>'2017-11-05','WYKONANIA'=>652],
    ['data'=>'2017-11-06','WYKONANIA'=>812],
    ['data'=>'2017-11-07','WYKONANIA'=>817],
    ['data'=>'2017-11-08','WYKONANIA'=>870],
    ['data'=>'2017-11-09','WYKONANIA'=>1070],
    ['data'=>'2017-11-10','WYKONANIA'=>1199],
    ['data'=>'2017-11-11','WYKONANIA'=>1206],
    ['data'=>'2017-11-12','WYKONANIA'=>1220],
    ['data'=>'2017-11-13','WYKONANIA'=>1421],
    ['data'=>'2017-11-14','WYKONANIA'=>1440],
    ['data'=>'2017-11-15','WYKONANIA'=>1904],
    ['data'=>'2017-11-16','WYKONANIA'=>1910],
    ['data'=>'2017-11-17','WYKONANIA'=>1962],
    ['data'=>'2017-11-18','WYKONANIA'=>2234],
    ['data'=>'2017-11-19','WYKONANIA'=>2305],
    ['data'=>'2017-11-20','WYKONANIA'=>2325],
    ['data'=>'2017-11-21','WYKONANIA'=>2250],
    ['data'=>'2017-11-22','WYKONANIA'=>2263],
    ['data'=>'2017-11-23','WYKONANIA'=>2821],
    ['data'=>'2017-11-24','WYKONANIA'=>2890],
    ['data'=>'2017-11-25','WYKONANIA'=>3411],
    ['data'=>'2017-11-26','WYKONANIA'=>3443],
    ['data'=>'2017-11-27','WYKONANIA'=>3501],
    ['data'=>'2017-11-28','WYKONANIA'=>4032]
];

final_array（）期望：

这段代码已经是我已经完成的但是我现在卡住了。

$x = 0;
while ($x<count($final_array))
{
    if ($new_array == null) {
    break;
    }
    else {
        for ($i = 0; $i < count($new_array); $i++) {
            if ($final_array[$x]['data'] == ($new_array[$i]['data']) {
                $final_array[$x]['WYKONANIA'] = $new_array['WYKONANIA']; 
            }
            else {
                array_push($final_array, "data", $new_array[$i]['data']);
                array_push($final_array, "WYKONANIA", $new_array[$i]['WYKONANIA']);
                array_push($final_array, "ESTYMACJA", $final_array[$x]['ESTYMACJA']);
            }
        }
    }
    $x++;
}

$myArray - first array
$new_array - second array
$final_array - final array.

Answer 1

// sort my_array in descending order of dates
rsort($my_array);

foreach($new_array as &$x) {
   foreach($my_array as $i) {
     // Because your dates have a different format, convert them to timestamp
     if(strtotime($x['data']) > strtotime($i['data'])) {
       $x['ESTYMACJA'] = $i['ESTYMACJA'];
       break;
     }
   }
}

demo

Answer 2

这将有助于

bivpois

合并表取决于相同的键

2 个答案: