关于volatile和const装饰

Question

我发现了一个关于c ++的问题 代码：

volatile const int a = 10;
int *p = const_cast<int*>(&a);
*p = 2;
cout << "value a="<< a << endl;
cout << "value *p=" <<*p << endl;
cout << "address a=" <<&a << endl;  //output 1！！
cout << "address p=" <<p << endl;

谁能告诉我为什么a的地址是1？

Answer 1

代码的行为是未定义。

Evalutation | # of places<br> ===============================<br> Bad | # of places with less than 40% "good" scores <br> Good | # of places with more than 40%, less than 70% "good" scores <br> Excellent | # of places with more than 70% "good" scores <br> 最初声明为a。

您尝试通过已放弃const的指针来更改其值。该语言不允许这样做。

const在这种情况下是红鲱鱼。