Question

我试图找到某种方式来点击一个按钮（菜单），它会改变网格（子菜单）的可见性，其中包含 XAML中的触发器。我是在vb.net上创建的，但我想知道在 XAML 中是否更容易做到？

Private Sub ShowSubmenu(SubmenuSettings e As Grid)
        Dim bk As Integer = VisualTreeHelper.GetChildrenCount(MainGrid)
        For i = 0 To bk - 1
            Dim g As Object = VisualTreeHelper.GetChild(MainGrid, i)
            If TypeOf g Is Grid Then g.Visibility = Visibility.Hidden
        Next
        SubmenuSettings.Visibility = Visibility.Visible
    End Sub

Private Sub Visibility(sender As Object)
        If sender Is btn1 Then
            ShowSubmenu(pdm1)
        End If
End Sub

Answer 1

您可以使用ToggleButton代替Button，我们的想法是根据ToggleButton的IsChecked属性切换网格可见性。

<Grid  Height="100" Width="100" Background="Green">
   <Grid.Style>
      <Style TargetType="Grid">
          <Setter Property="Visibility" Value="Collapsed"/>
          <Style.Triggers>
             <DataTrigger Binding="{Binding IsChecked,ElementName=btnFirst}" Value="True">
                 <Setter Property="Visibility" Value="Visible"/>
              </DataTrigger>
          </Style.Triggers>
       </Style>
   </Grid.Style>
</Grid>

 <ToggleButton x:Name="btnFirst" Content="BtnFirst" Height="100" Width="100" />

Answer 2

你可以给你的网格＆＃34; X：名称=＆＃34; gridName＆＃34; ＆＃34;，然后在点击按钮时从代码执行＆＃34; gridName.Visibility = Visibility.Collapsed＆＃34; （如你所愿，折叠或隐藏）。＆＃34;

在按钮上更改网格的可见性在Xaml中单击

2 个答案: