Question

有三个表：users，ap_name_bank_m和ap_name_bank_h。用户表有三列＆＃39; name_eng＆＃39; （英文用户名），＆＃39; name_gdn_eng＆＃39;（用户英文监护人姓名）和＆＃39;类别＆＃39;。

ap_name_bank_m和ap_name_bank_h是每个名称类别的名称语料库：＆＃39; m＆＃39;或者＆＃39; h＆＃39;。

当一行更新时，我想检查两个表中的每个单词是否存在于两个表ap_name_bank_m和ap_name_bank_h中的任何一个。

分配的类别越高。我写的下面的代码进入了无限循环，我得到了＃34; MySQL服务器已经消失了错误＆＃34;。有人能告诉我哪里错了吗？

假设name_eng和name_gdn_eng只包含带空格的单词，而不包含任何其他单词。

DELIMITER $$
create trigger set_cat before update on users_table for each row
BEGIN
declare words text;
declare word varchar(50);
declare num_m int default 0;
declare num_h int default 0;
declare len int default 0;

set words = concat(new.name_eng,' ',new.name_gdn_eng);

iterator:
LOOP
set word = substring_index(words,' ',1);
set num_m = EXISTS(select 1 from ap_name_bank_m where name=word) + num_m;
set num_h = EXISTS(select 1 from ap_name_bank_h where name=word) + num_h;

set words = trim(replace(words,word,''));
END LOOP iterator;

if (num_m > num_h) then set new.category='M'; end if;
if (num_h > num_m) then set new.category='H'; end if;
END $$
DELIMITER ;

Answer 1

我找到了一个更好的方法来做到这一点。不需要循环。

BEGIN
declare words text;
declare word varchar(50);
declare num_m int default 0;
declare num_h int default 0;

set words = concat(new.name_eng,' ',new.name_gdn_eng);

set num_h = (select count(*) from ap_name_bank_h where match(name) against (words in natural language mode));

set num_m = (select count(*) from ap_name_bank_m where match(name) against(words in natural language mode));

/*
iterator:
LOOP
set word = substring_index(words,' ',1);
set num_m = EXISTS(select 1 from ap_name_bank_m where name=word) + num_m;
set num_h = EXISTS(select 1 from ap_name_bank_h where name=word) + num_h;

set words = trim(replace(words,word,''));
END LOOP iterator;*/

if (num_m > num_h) then set new.category='M'; end if;
if (num_h > num_m) then set new.category='H'; end if;
END

MySQL触发插入文本进入无限循环

1 个答案: