Question

我需要使用PHP从值搜索中删除一些字符。我在下面解释我的代码。

当前数据

$datArr = array(
    array(
        "name" => "Ram",
        "id" => 1,
        "date" => "12/04/2017 05:31:57 AM"
    ),
    array(
        "name" => "Rahim",
        "id" => 5,
        "date" => "12/03/2017 12:31:57 PM"
    ),
    array(
        "name" => "Raj",
        "id" => 4,
        "date" => "12/04/2017 05:31:57 PM"
    )
);

预期输出

$datArr = array(
    array(
        "name" => "Ram",
        "id" => 1,
        "date" => "12/04/2017 05:31:57"
    ),
    array(
        "name" => "Rahim",
        "id" => 5,
        "date" => "12/03/2017 12:31:57"
    ),
    array(
        "name" => "Raj",
        "id" => 4,
        "date" => "12/04/2017 05:31:57"
    )
);

从上面的数组中有一个date字段值，我需要使用PHP从所有日期删除AM/PM。

Answer 1

使用rtrim删除这样的尾部字符，

$datArr = array_map(function($v){
    $v['date'] = rtrim($v['date'], " APMapm");
    return $v;
}, $datArr);

Answer 2

$datArr=array(array("name"=>"Ram","id"=>1,"date"=>"12/04/2017 05:31:57 AM"),array("name"=>"Rahim","id"=>5,"date"=>"12/03/2017 12:31:57 PM"),array("name"=>"Raj","id"=>4,"date"=>"12/04/2017 05:31:57 PM"));

使用foreach循环遍历数组。当涉及到日期值时，请执行以下操作

将日期字符串转换为datetime对象

$time = strtotime($dateKeyValueInArray);

现在设置此时间戳的日期格式

$newformat = date('Y-m-d',$time);

使用

查看输出

echo $newformat;

参考链接是 Converting string to Date and DateTime https://www.w3schools.com/php/func_date_date_format.asp

希望有所帮助：）

Answer 3

您可以使用str_replace()循环<{1}}来执行此操作

<强>代码

foreach

<强>输入

foreach ($datArr as &$dat) {
    $dat['date'] = str_replace([' AM', ' PM'], "", $dat['date']);
}

<强>输出

$datArr = array(
    array(
        "name" => "Ram",
        "id" => 1,
        "date" => "12/04/2017 05:31:57 AM"
    ),
    array(
        "name" => "Rahim",
        "id" => 5,
        "date" => "12/03/2017 12:31:57 PM"
    ),
    array(
        "name" => "Raj",
        "id" => 4,
        "date" => "12/04/2017 05:31:57 PM"
    )
);

Answer 4

尝试使用foreach循环进行此操作

$datArr=array(array("name"=>"Ram","id"=>1,"date"=>"12/04/2017 05:31:57 AM"),array("name"=>"Rahim","id"=>5,"date"=>"12/03/2017 12:31:57 PM"),array("name"=>"Raj","id"=>4,"date"=>"12/04/2017 05:31:57 PM"));

print_r($datArr);
foreach($datArr as $key=>$value)
{
    $datArr[$key]['date'] = date('m/d/Y H:i:s',strtotime($value['date']));
}

echo "after";
print_r($datArr);

此代码的输出

    Array
(
    [0] => Array
        (
            [name] => Ram
            [id] => 1
            [date] => 12/04/2017 05:31:57 AM
        )

    [1] => Array
        (
            [name] => Rahim
            [id] => 5
            [date] => 12/03/2017 12:31:57 PM
        )

    [2] => Array
        (
            [name] => Raj
            [id] => 4
            [date] => 12/04/2017 05:31:57 PM
        )

)
afterArray
(
    [0] => Array
        (
            [name] => Ram
            [id] => 1
            [date] => 12/04/2017 05:31:57
        )

    [1] => Array
        (
            [name] => Rahim
            [id] => 5
            [date] => 12/03/2017 12:31:57
        )

    [2] => Array
        (
            [name] => Raj
            [id] => 4
            [date] => 12/04/2017 17:31:57
        )

)

Answer 5

试试这个。这是一个简单易懂的例子。 substr函数用于将字符串的一部分从0开始到length - 2以排除AM/PM

foreach($datArr as $key => $value){
    $datArr[$key]['date'] = substr($value['date'], 0, strlen($value['date'])-2);
}
print_r($datArr);

快乐编码： - ）

Answer 6

您可以使用正则表达式通过循环删除不需要的单词。

foreach($datArr as &$i)
{
     $i['date']=preg_replace('[AM|PM]',"",$i['date']);
}
print_r ($datArr);

输出

Array
(
[0] => Array
    (
        [name] => Ram
        [id] => 1
        [date] => 12/04/2017 05:31:57 
    )

[1] => Array
    (
        [name] => Rahim
        [id] => 5
        [date] => 12/03/2017 12:31:57 
    )

[2] => Array
    (
        [name] => Raj
        [id] => 4
        [date] => 12/04/2017 05:31:57 
    )

)

Answer 7

<?php
$datArr=array(array("name"=>"Ram","id"=>1,"date"=>"12/04/2017 05:31:57 AM"),array("name"=>"Rahim","id"=>5,"date"=>"12/03/2017 12:31:57 PM"),array("name"=>"Raj","id"=>4,"date"=>"12/04/2017 05:31:57 PM"));
echo "<pre>";
print_r($datArr);

$a = array();
foreach ($datArr as &$str) {
    $str = str_replace('PM', ' ', $str);
    $str = str_replace('AM', ' ', $str);
    $a[]=$str;
}
print_r($a);
?>

check fiddle

Answer 8

只是说我的作品，如果您只是使用字符串函数直接删除AM / PM，我认为您可能会有错误的日期时间。如果你这样做，你将如何区分5AM到5PM？现在你将得到错误的数据。

如果您在5中取出PM，那么您需要将其格式化为军事时间（17）。要做到这一点，您需要先每次转换。您可以使用DateTime：

执行此操作

$datArr = array_map(function($e){
    $dt = new DateTime($e['date']);
    $e['date'] = $dt->format('m/d/Y H:i:s'); // convert me into correct time

    return $e;
}, $datArr);

Sample Output

如何使用PHP从字符串中删除一些字符

8 个答案: