在处理第二张牌之前为每位玩家交易一张牌 - 在Python中使用二十一点游戏

时间:2017-12-05 04:00:42

标签: python python-3.x blackjack

我在Python中制作了以下代码。 deck = deck_of_cards()。我的问题是如何修复第二个功能,以便它必须在交易第二张牌之前向每个玩家发放第一张牌。它现在的方式似乎是在向其他玩家发牌之前向玩家发放两张牌,我不知道如何修复它。

import random
def deck_of_cards():
    suits = ['D', 'C', 'H', 'S']
    denominations = ['2', '3', '4', '5', '6', '7', '8', 
                     '9', 'T', 'J', 'Q', 'K', 'A']
    deck = []
    for suit in suits:
        for denomination in denominations:
            ds = denomination + suit
            deck.append(ds)

    random.shuffle(deck)      
    return deck

def deal_cards(deck, players):
    hands = []

    for j in range(players):
        player_hand = []
        for i in range(2):
            cards = deck.pop(0)
            player_hand.append(cards)

        hands.append(player_hand)  
    return hands 

1 个答案:

答案 0 :(得分:3)

你需要交换你的for循环,所以你迭代所有玩家的第一辆车,然后第二辆:

def deal_cards(deck, players):
    hands = [[] for player in range(players)]

    for _ in range(2):
        for hand in hands:
            hand.append(deck.pop(0))

    return hands