Question

我试图这样做，当用户输入他们的名字，姓氏和当前位置时，日期/时间应自动输入（记录）到日期列并保存。然后它应该显示表中的所有行。我一直收到错误（下面）。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 

<head> 
<title></title> 
</head>

<center>
    <h2> ACW LOCATION TRACOR </h2>
</center>

<body>
    <table width="200" border="5" cellpadding="0" cellspacing="1">
        <tr>
            <th> Username </th>
            <th> First_Name </th>
            <th> Surname </th>
            <th> Current_Location </th>
            <th> TimeStamp </th>
        <tr>

<?php
$server = 'SQL2008.net.dcs.hull.ac.uk';

$connectionInfo = array("Database"=>"rde_531545");
$conn = sqlsrv_connect($server,$connectionInfo);
$query='create table Location ';
$query .= '(Username int NOT NULL IDENTITY(500, 23), First_Name varchar(50) NOT NULL, Surname varchar(50) NOT NULL, Current_Location varchar(50) NOT NULL, Date Datetime NOT NULL, PRIMARY KEY (Username))';
$result = sqlsrv_query($conn, $query);

if (!$result){
 if( ($errors = sqlsrv_errors() ) != null){
    foreach( $errors as $error ){
        echo "<p>Error: ".$error[ 'message']."</p>";
        }
    }
}
else{
    echo "<p>DB successfully created</p>";
    }
sqlsrv_close($conn);

date_default_timezone_set('Europe/London');
$Date =  new DateTime();
$DateStr = $Date->format('Y-m-d H:i:s');

$server = 'SQL2008.net.dcs.hull.ac.uk'; 
$connectionInfo = array( "Database"=>"rde_531545"); 
$conn = sqlsrv_connect($server,$connectionInfo); 
$insert_query = "INSERT INTO Location (First_Name, Surname, Current_Location, Date) VALUES (?, ?, ?, ?)"; 
$params = array("Jon","Doey","Leeds", $DateStr); 
$result = sqlsrv_query($conn,$insert_query,$params);
$params = array("John","Doe","Hull", $DateStr);
$result = sqlsrv_query($conn,$insert_query,$params);

$SelectQuery='SELECT Username, First_Name, Surname, Current_Location, Date FROM Location'; 
$results = sqlsrv_query($conn, $SelectQuery); 

while($row = sqlsrv_fetch_array($results, SQLSRV_FETCH_ASSOC)){ 
    echo "<tr><td>".$row['Username']."</td><td>".$row['First_Name']."</td><td>".$row['Surname']."</td><td>".$row['Current_Location']."</td><td>".$dateStr = $Date->format("Y-m-d H:i:s")."</td></tr>";
} 

sqlsrv_close($conn);

?>

    </table>
</body> 
</html>

期望的输出：

512 |简| Doe |船体| 2012/12/12 18:24:45 PM

我一直收到此错误，也没有将日期保存到数据库中：

可捕获的致命错误：第69行的C：\ RDEUsers \ NET \ 531545 \ LocationPOST.php中无法将类DateTime的对象转换为字符串

PHP无法从数据库插入和检索数据

0 个答案: