我似乎无法使用EF4成功更新MVC2中的多对多图。我认为最简单的事情是Clear()整个图形,调用SaveChanges(),然后在最后重建再次调用SaveChanges()的图形,但它不起作用。但是,我所有其他属性都是。首先,我的行动方法:
public ActionResult EditReview(int id)
{
var game = _gameRepository.GetGame(id);
var genres = _gameRepository.AllGenres();
var platforms = _gameRepository.AllPlatforms();
var model = new AdminGameViewModel { GameData = game, AllGenres = genres, AllPlatforms = platforms };
return View(model);
}
//
// POST: /Admin/EditReview/5
[HttpPost]
public ActionResult EditReview([Bind(Prefix="GameData")]Game existingGame, int[] PlatformIDs)
{
try
{
_gameRepository.ValidateGame(existingGame, PlatformIDs);
}
catch(RulesException ex)
{
ex.CopyTo(ModelState);
ex.CopyTo(ModelState, "GameData");
}
if (ModelState.IsValid)
{
return RedirectToAction("Index");
}
else
{
var genres = _gameRepository.AllGenres();
var platforms = _gameRepository.AllPlatforms();
var model = new AdminGameViewModel { GameData = existingGame, AllGenres = genres, AllPlatforms = platforms };
return View(model);
}
}
repo本身(ValidateGame和SaveGame是相关方法):
namespace HandiGamer.Domain.Concrete
{
public class HGGameRepository : IGameRepository
{
private HGEntities _siteDB = new HGEntities();
public List<Game> Games
{
get { return _siteDB.Games.ToList(); }
}
public void ValidateGame(Game game, int[] PlatformIDs)
{
var errors = new RulesException<Game>();
if (string.IsNullOrEmpty(game.GameTitle))
{
errors.ErrorFor(x => x.GameTitle, "A game must have a title");
}
if (string.IsNullOrEmpty(game.ReviewText))
{
errors.ErrorFor(x => x.ReviewText, "A review must be written");
}
if (game.ReviewScore <= 0 || game.ReviewScore > 5)
{
errors.ErrorFor(x => x.ReviewScore, "A game must have a review score, and the score must be between 1 and 5");
}
if (string.IsNullOrEmpty(game.Pros))
{
errors.ErrorFor(x => x.Pros, "Each game review must have a list of pros");
}
if (string.IsNullOrEmpty(game.Cons))
{
errors.ErrorFor(x => x.Cons, "Each game review must have a list of cons");
}
if (PlatformIDs == null || PlatformIDs.Length == 0)
{
errors.ErrorForModel("A game must belong to at least one platform");
}
if (game.GenreID == 0)
{
errors.ErrorFor(x => x.GenreID, "A game must be associated with a genre");
}
if (errors.Errors.Any())
{
throw errors;
}
else
{
SaveGame(game, PlatformIDs);
}
}
public void SaveGame(Game game, int[] PlatformIDs)
{
_siteDB.Games.Attach(game);
if (game.GameID > 0)
{
_siteDB.ObjectStateManager.ChangeObjectState(game, System.Data.EntityState.Modified);
game.Platforms.Clear();
}
else
{
_siteDB.ObjectStateManager.ChangeObjectState(game, System.Data.EntityState.Added);
}
foreach (int id in PlatformIDs)
{
Platform plat = _siteDB.Platforms.Single(pl => pl.PlatformID == id);
game.Platforms.Add(plat);
}
game.LastModified = DateTime.Now;
_siteDB.SaveChanges();
}
public Game GetGame(int id)
{
return _siteDB.Games.Include("Genre").Include("Platforms").SingleOrDefault(g => g.GameID == id);
}
public IEnumerable<Game> GetGame(string title)
{
return _siteDB.Games.Include("Genre").Include("Platforms").Where(g => g.GameTitle.StartsWith(title)).AsEnumerable<Game>();
}
public List<Game> GetGamesByGenre(int id)
{
return _siteDB.Games.Where(g => g.GenreID == id).ToList();
}
public List<Game> GetGamesByGenre(string genre)
{
return _siteDB.Games.Where(g => g.Genre.Name == genre).ToList();
}
public List<Game> GetGamesByPlatform(int id)
{
return _siteDB.Games.Where(g => g.Platforms.Any(p => p.PlatformID == id)).ToList();
}
public List<Game> GetGamesByPlatform(string platform)
{
return _siteDB.Games.Where(g => g.Platforms.Any(p => p.Name == platform)).ToList();
}
public List<Genre> AllGenres()
{
return _siteDB.Genres.OrderBy(g => g.Name).ToList();
}
public List<Platform> AllPlatforms()
{
return _siteDB.Platforms.OrderBy(p => p.PlatformID).ToList();
}
}
}
我很难过。
答案 0 :(得分:1)
凯文 哦,这有点复杂,迫使你回到EFv1模式,因为使用M:M,你没有外键可以依靠,你就会被物体困住。
当您添加游戏时,您确实希望添加关系(即连接表中的一行),但您不希望添加平台,因为它只是一个参考。
我实际上并没有这样做,但我认为如果你可以将它拆开然后在游戏附加并标记添加后重建平台集合会更容易。否则,如果添加整个图表,则会标记所有内容。
EF的问题在于,如果你附加游戏,你也会得到相关的东西。可能有一个更清晰的模式,但我的想法是将游戏从游戏中分离出来,将游戏附加到上下文中,将其标记为已添加。然后我会将平台附加到上下文中。它们将“不变”。然后将它们添加到games.platform集合中。平台仍将保持不变,但:将被理解。
你可能已经尝试过了。我必须自己做,并观察所有事物的实体状态,因为我一直在查看发生了什么。关键是EF需要跟踪已添加的关系并且是新的(并且会导致连接表中的行被添加),但要了解平台不是新的。
HTH 朱莉