Ansible - 从playbook输出中隐藏with_dict变量

时间:2017-12-04 20:28:23

标签: ansible

我有一个剧本,我使用字典变量文件和includes_tasks播放。我的问题是playbook在运行时显示变量。我尝试了no_log:True和ignore_errors:True但没有任何区别。我使用的是ansible版本2.4.1.0

以下是剧本任务:

tasks:
  - name: "Install License and Remove Default Identifier"
    include_tasks: includes/junos_license.yml
    with_dict: "{{ vsrx  }}"

以下是运行剧本的输出:

TASK [Install License and Remove Default Identifier] 

***************************************************************************
msg: All items completed

results: [
  {
    "item": {
      "key": "vsrx-02", 
      "value": {
        "Hostname": "vsrx-02", 
        "IP_Address": "192.168.1.211"
      }
    }, 
    "_ansible_item_result": true, 
    "include": "includes/junos_license.yml", 
    "include_variables": {}
  }, 
  {
    "item": {
      "key": "vsrx-01", 
      "value": {
        "Hostname": "vsrx-01", 
        "IP_Address": "192.168.1.209"
      }
    }, 
    "_ansible_item_result": true, 
    "include": "includes/junos_license.yml", 
    "include_variables": {}
  }
] 
included: /home/ansible/junos_base_config/includes/junos_license.yml for 
localhost
included: /home/ansible/junos_base_config/includes/junos_license.yml for 
localhost

1 个答案:

答案 0 :(得分:2)

使用loop_control

tasks:
  - name: "Install License and Remove Default Identifier"
    include_tasks: includes/junos_license.yml
    with_dict: "{{ vsrx }}"
    loop_control:
      label: "{{ item.key }}"