已移除已移除的移除
答案 0 :(得分:1)
我会使用相关查询。有很多方法可以做到这一点:作为SELECT子句中的子查询,或作为WHERE子句中的子查询。
在这种情况下,我实现了第二个选项:
SELECT
person_name,
order_name
FROM Persons
INNER JOIN Orders ON Persons.person_id = Orders.person_id
WHERE
(
cost = (
SELECT MIN(cost)
FROM Orders
WHERE
(Orders.person_id = Persons.person_id)
)
)
答案 1 :(得分:0)
删除order=
并添加AS order_name
这样的事情:
SELECT p.person_name
, ( SELECT o.order_name
FROM orders o
WHERE o.person_id = p.person_id
ORDER BY o.cost ASC
LIMIT 1
) AS order_name
FROM person p
ORDER BY p.person_name
答案 2 :(得分:0)
MIN
您只需加入2个表并使用worker_processes 1;
error_log /var/log/nginx/error.log warn;
pid /var/run/nginx.pid;
events {
worker_connections 1024;
}
http {
include mime.types;
default_type application/octet-stream;
upstream hello-akka{
server localhost:9000;
}
server {
listen 80;
location / {
root /usr/share/nginx/html;
index index.html index.htm;
}
location /akka {
proxy_pass http://hello-akka;
}
location /assets {
root /var/www;
}
}
}
即可完成此操作。