如何从刺痛角色获取不同的字符串

Question

我有一个字符串"abc"。想要从字符串字符中获取所有不同的字符串。

#include<bits/stdc++.h>
using namespace std;

// Function to print all sub strings
void subString(string s, int n) 
{
     // Pick starting point in outer loop
    // and lengths of different strings for
    // a given starting point
    for (int i = 0; i < n; i++) 
       for (int len = 1; len <= n - i; len++)
           cout << s.substr(i, len) << endl;
}

 // Driver program to test above function
 int main() 
 {
    string s = "abc";
    subString(s,s.length());
    return 0;
 }

期待：

  

a b c ab ac bc abc

实际输出：

  

a b c ab bc abc

Answer 1

请参阅以下解决方案：

#include <iostream>

using namespace std;

int main()
{
    string input = "abc";
    for (int length = 0; length < input.length(); length++) {
        for (int offset = 0; offset <= input.length() - length; offset++) {
            cout << input.substr(offset, length) + "\n";
        }
    }
    cout << input;

    return 0;
}