我正在尝试使用字符填充C ++中的2D向量,但是当我运行此代码时,它以一行字符(*..
)结束。
如何像这样填充2D矢量:
*.*
.**
#include <iostream>
#include <vector>
int main()
{
std::vector<std::vector<char> > vec2D;
std::vector<char> rowV;
unsigned int row=2;
unsigned int col=3;
char c;
unsigned int temp=0;
while(temp!=col)
{
while(rowV.size()!=row)
{
std::cin>>c;
rowV.push_back(c);
}
vec2D.push_back(rowV);
++temp;
}
return 0;
}
答案 0 :(得分:1)
每次插入后都应清除rowV
,否则它将被填满,不会添加其他字符。此外,row
应由col
交换,反之亦然,否则您将获得3x2(而不是2x3)的2D矢量。
while(temp!=row)
{
while(rowV.size()!=col)
{
std::cin>>c;
rowV.push_back(c);
}
vec2D.push_back(rowV);
rowV.clear(); // clear after inserting
++temp;
}
答案 1 :(得分:0)
了解[用空的1D向量推回2DVector]是什么样子。 请参见下面的示例。
#include <algorithm>
#include <cmath>
#include <iostream>
#include <vector>
using namespace std;
//-v-----A FUNCTION TO PRINT 2D VECTORS
template<typename T> //We don't know what type the elements are yet, so we use a template
void printVec2D(vector<vector<T>> a) // a is the name of our input 2Dvector of type (T)
{
for (int i = 0; i < a.size(); i++) {// a.size() will equal the number of rows (i suppose rows/columns can depend on how you look at it)
for (int j = 0; j < a[i].size(); j++) {// a[i].size() is the size of the i'th row (which equals the number of columns, foro a square array)
std::cout << a[i][j] << "\t";
}
std::cout << "\n";
}
return;
}
//-^--------
int main()
{
int X = 3; int Y = 3;
int VectorAsArray[3][3] = {{1,2,3},
{14,15,16},
{107,108,109}};
vector<vector<int>> T;
for (int i = 0; i < X; i++)
{
T.push_back({});// We insert a blank row until there are X rows
for (int j = 0; j < Y; j++)
{
T[i].push_back(VectorAsArray[i][j]); //Within the j'th row, we insert the element corresponding to the i'th column
}
}
printVec2D(T);
//system("pause"); //<- I know that this command works on Windows, but unsure otherwise( it is just a way to pause the program)
return 0;
}