Mon Dec 4 19:36:23 2017, 98
Tues Dec 5 19:36:28 2017, 99
Wed Dec 6 19:36:21 2017, 95
Thur Dec 7 19:36:23 2017, 89
Fri Dec 8 19:36:20 2017, 93
Sun Dec 10 19:36:23 2017, 98
Mon Dec 11 19:36:25 2017, 97
目前我正在使用以下查询。
--------------------Table1-------------
Table1Id item SaleId Dimensions
1 test1 41 10*11*12
2 test2 41 13*14*15
--------------------Table2-------------
Table2Id item Description
1 test1 Test element1 desc 1
2 test1 Test element1 desc 2
3 test2 Test element2 desc 1
4 Test2 Test element2 desc 2
但我想要那样的结果(需要将Table1.item与表2中的项目的第一条记录连接起来)
select Table1.Table1Id, Table1.item, Table1.Dimensions, Table2.Description
on Table1.item = Table2.item
where Table1.SaleId = 41
答案 0 :(得分:2)
处理此问题的最典型方法是使用ANSI标准row_number()
:
Select t1.Table1Id, t1.item, t1.Dimensions, t2.Description
from table1 t1 join
(select t2.*, row_number() over (partition by t2.item order by t2.table2id desc) as seqnum
from table2 t2
) t
on t1.item = t2.item and t2.seqnum = 1
where t1.SaleId = 41;