我有10个不同大小的UILabel,我想将它们排成3行,并且所有行都有前导对齐,如果每行的最后一项不能适合父视图的剩余空间,则必须转到下一行。我怎么能用UIStackview做到这一点?
答案 0 :(得分:0)
您可以尝试做类似的事情:
您的ViewController
for item in array {
let someView = VPView(frame: CGRect(x: 0, y: 0, width: 70, height: 20))
someView.translatesAutoresizingMaskIntoConstraints = false
stackView.addArrangedSubview(someView)
}
UIView类:
class VPView: UIView {
let myLabel = UILabel()
override init(frame: CGRect) {
super.init(frame: frame)
self.addLabel()
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
}
func addLabels() {
//Mark: - Styles
let labelH: CGFloat = 15
let labelW: CGFloat = 70
//MARK: - My Label
self.myLabel.frame = CGRect(x: 0, y: 0, width: labelW, height: labelH)
self.myLabel.backgroundColor = UIColor.blue
self.myLabel.textAlignment = NSTextAlignment.center
self.myLabel.numberOfLines = 0
self.addSubview(self.myLabel)
self.myLabel.translatesAutoresizingMaskIntoConstraints = false
self.myLabel.heightAnchor.constraint(equalToConstant: labelH).isActive = true
self.myLabel.widthAnchor.constraint(equalToConstant: labelW).isActive = true
self.myLabel.topAnchor.constraint(equalTo: self.topAnchor).isActive = true
self.myLabel.leadingAnchor.constraint(equalTo: self.leadingAnchor).isActive = true
}
}