Question

PHP中的自定义函数在某些情况下不起作用。

代码：

<?php
function short_format_indian_c($n) {
    $precision = 3;
    $n_format = number_format($n / 1000, $precision);
    $n_format = number_format($n_format, 2);
    $n_format = $n_format + 0;
    $n_format = $n_format . ' K';
    return $n_format;
}
?>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script>
    var checkState = function(){  
        var tq = jQuery('#tq');
        tq.html(18000);
    }
    checkState();
    setInterval(checkState, 1000);
</script>
<?php $tq = '<span id="tq"></span>';?><?php echo short_format_indian_c($tq); ?>

如果我使用 echo short_format_indian_c（1800），它会将结果显示为 18 K 。

但是当我使用 echo short_format_indian_c（$ tq）时，它会将结果显示为 0 K ，其中 $ tq 也是 18000

Answer 1

好吧，你的函数需要一个参数。当你在代码中调用它时

<?php echo short_format_indian_c($tq); ?>

您传递$ tq作为参数。 $ tq目前等于“”

<?php $tq = '<span id="tq"></span>';?>

在函数内部，您对参数执行除法，在本例中是一个字符串。由于该过程，字符串将被转换为int并且将等于0.因此，您将得到0 K.

另一方面，当您传递18000作为参数时，一切都会按预期工作。

Answer 2

<?php 
echo short_format_indian_c($tq); // There $tq not have any number only value thats why this not give a proper output.

?>


    <?php
    //This code run only server side.

    function short_format_indian_c($n) {
        $precision = 3;
        $n_format = number_format($n / 1000, $precision);
        $n_format = number_format($n_format, 2);
        $n_format = $n_format + 0;
        $n_format = $n_format . ' K';
        return $n_format;
    }
   // As per User need.

   function kFormatter($num) {
      // return ($num > 999) ?(round(($num/1000),2).'K':$num; //Not return K for less than 1000 ;
      return round(($num/1000),2).'K'; // work for all numbers

    } 
    ?>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
    <script>
        //This part only run at client side.
        function kFormatter(num) {
          // return num > 999 ? (num/1000).toFixed(1) + 'K' : num; //Not return K for less than 1000 ;
          return (num/1000).toFixed(1) + 'K'; // work for all numbers

        } 
        // Function for all format indian Currency.

       function short_format_indian_c(num) {


if(num < 1000)
      {
        return num; // For Less then 1000
      }
      else if(num >= 1000 && num < 99999)
      {
        return (num/1000).toFixed(1) + 'K'; // for 1000 multiplier till 99999
      }
      else if(num >= 100000 && num < 9999999)
      {
        return (num/100000).toFixed(1) + 'L'; // for 100000 multiplier till 9999999
      }
      else if(num >= 10000000 && num < 999999999)
      {
        return (num/10000000).toFixed(1) + 'C'; // for 10000000 multiplier till 999999999
      }
      else
      {
        return num; // For all other num instead
      }

    } 
        var checkState = function(){  
            var tq = jQuery('#tq');

            tq.html(short_format_indian_c(18000));
            // This will provide an output as 18K in element have id is tq;

        }
    checkState();
    setInterval(checkState, 1000);
    </script>
    <?php 
    $tq = '<span id="tq"></span>'; // Wrong way to assign html value in a php variable.
    $tq  = '18000'; // this will work instead.

    ?>
    <?php 
    echo short_format_indian_c($tq); // There $tq not have any number only value thats why this not give a proper output.

    ?>

注意！如果您在客户端需要结果，那么您还需要为javascript编写此函数; Fiddle

PHP中的自定义函数无法正常工作

2 个答案: