使用php mysql

时间:2017-12-04 05:17:37

标签: php html css mysql

我正在尝试从数据库中获取图像,并使用php mysql在每行中显示2个图像。我的代码只显示2张图像,其余图像不显示。这是代码

CSS

.image-inner {
  position: relative;
  width: 150px;
  display: inline-block;

}

PHP

$res=mysql_query("select * from table1");
echo "<div class=view1>";
$i=0;
echo "<table>";
    echo "<tr>";
        while($row=mysql_fetch_array($res)){
            if($i % 4 == 0) {
                echo "<td>"; 
                    echo '<img src="data:image/jpeg;base64,'.base64_encode($row['image1'] ).'" class=image-inner height="200" width="200"/>';
                    echo "<br>";
                    echo $row['name1'];
                    echo "<br>";
                    echo $row['designation'];
            }
                echo "</td>";
            $i++;
        }
   echo "</tr>";
   echo "</table>";
?>

0 个答案:

没有答案