如何按字母顺序对python列表进行排序，同时考虑列表项后面的编号。请参阅下面的示例和用于排序的代码。 请注意，如果数字低于10，则无法在代码中插入零。
原始列表：
[＆＃39; drawing-n-3＆＃39;，＆＃39; drawing-n-2＆＃39;，＆＃39; drawing-n-1＆＃39;，＆＃39; drawing-n -7＆＃39 ;, ＆＃39; drawing-n-6＆＃39;，＆＃39; drawing-n-5＆＃39;，＆＃39; drawing-n-4＆＃39;，＆＃39; drawing-n-9＆＃39 ;， ＆＃39; drawing-n-8＆＃39;，＆＃39; drawing-n-16＆＃39;，＆＃39; drawing-n-15＆＃39;，＆＃39; drawing-n-14＆＃39 ;， ＆＃39; drawing-n-13＆＃39;，＆＃39; drawing-n-12＆＃39;，＆＃39; drawing-n-11＆＃39;，＆＃39; drawing-n-10＆＃39 ;， ＆＃39;绘图N-17＆＃39;]
排序列表：
[＆＃39; drawing-n-1＆＃39;，＆＃39; drawing-n-10＆＃39;，＆＃39; drawing-n-11＆＃39;，＆＃39; drawing-n -12＆＃39 ;, ＆＃39; drawing-n-13＆＃39;，＆＃39; drawing-n-14＆＃39;，＆＃39; drawing-n-15＆＃39;，＆＃39; drawing-n-16＆＃39 ;， ＆＃39; drawing-n-17＆＃39;，＆＃39; drawing-n-2＆＃39;，＆＃39; drawing-n-3＆＃39;，＆＃39; drawing-n-4＆＃39 ;， ＆＃39; drawing-n-5＆＃39;，＆＃39; drawing-n-6＆＃39;，＆＃39; drawing-n-7＆＃39;，＆＃39; drawing-n-8＆＃39; drawing-n-8＆＃39 ;， ＆＃39;绘图N-9＆＃39;]
期望列表输出：
[＆＃39; drawing-n-1＆＃39;，＆＃39; drawing-n-2＆＃39;，＆＃39; drawing-n-3＆＃39;，＆＃39; drawing-n -4＆＃39 ;, ＆＃39; drawing-n-5＆＃39;，＆＃39; drawing-n-6＆＃39;，＆＃39; drawing-n-7＆＃39;，＆＃39; drawing-n-8＆＃39; drawing-n-8＆＃39 ;， ＆＃39; drawing-n-9＆＃39;，＆＃39; drawing-n-10＆＃39;，＆＃39; drawing-n-11＆＃39;，＆＃39; drawing-n-12＆＃39 ;， ＆＃39; drawing-n-13＆＃39;，＆＃39; drawing-n-14＆＃39;，＆＃39; drawing-n-15＆＃39;，＆＃39; drawing-n-16＆＃39 ;， ＆＃39;绘图N-17＆＃39;]
代码：
dwg_number_keys = [key for key in kwargs if key.startswith("drawing-n-")]
print dwg_number_keys
print sorted(dwg_number_keys, key=str.lower)
答案 0 :(得分：0)
将其从字符串解析为整数以进行排序： -
>>> begin = len("drawing-n-")
>>> sorted(dwg_number_keys, key=lambda s:int(s[len("drawing-n-"):]))
['drawing-n-1', 'drawing-n-2', 'drawing-n-3', 'drawing-n-4', 'drawing-n-5', 'drawing-n-6', 'drawing-n-7', 'drawing-n-8', 'drawing-n-9', 'drawing-n-10', 'drawing-n-11', 'drawing-n-12', 'drawing-n-13', 'drawing-n-14', 'drawing-n-15', 'drawing-n-16', 'drawing-n-17']
答案 1 :(得分：0)
像这样：
>>> my_list = ['drawing-n-3', 'drawing-n-2', 'drawing-n-1', 'drawing-n-7', 'drawing-n-6', 'drawing-n-5', 'drawing-n-4', 'drawing-n-9', 'drawing-n-8', 'drawing-n-16', 'drawing-n-15', 'drawing-n-14', 'drawing-n-13', 'drawing-n-12', 'drawing-n-11', 'drawing-n-10', 'drawing-n-17']
>>> sorted(my_list, key=lambda s:int(s[s.rindex('-')+1:]))
['drawing-n-1', 'drawing-n-2', 'drawing-n-3', 'drawing-n-4', 'drawing-n-5', 'drawing-n-6', 'drawing-n-7', 'drawing-n-8', 'drawing-n-9', 'drawing-n-10', 'drawing-n-11', 'drawing-n-12', 'drawing-n-13', 'drawing-n-14', 'drawing-n-15', 'drawing-n-16', 'drawing-n-17']
key lambda只是解析在' - '标记后的每个字符串的最后一个找到的整数。
答案 2 :(得分：0)
如果格式与您的格式一致
，这将为您提供所需的内容 lambda x: int(x.split('-')[-1])