Question

def parse_to_number(var):
    try:
        return int(var)
    except ValueError:
        return 0
inputFile = open("Students_1.txt" , 'w')
inputFile.write("John Smith 80 90\n")
inputFile.write("Ryan Brown 80 60\n")
inputFile.write("Anna Myers 95 85\n")
inputFile.close()
inputFile = open("Students_1.txt" , 'r')
for line in inputFile:
    y = line.split()
    first_name = y[0]
    last_name = y[1]
    math_grade = parse_to_number(y[2])
    chem_grade = parse_to_number(y[3])
    ave = (math_grade + chem_grade)/2.0
    print(math_grade, chem_grade, ave)

我试图让最终结果看起来像一个列表，但只是将平均值添加到结尾，所以它显示三组不同的数字而不是两组这样的数字，但将其保存到标题为＆＃的输出文件中34; Students_2.txt＆＃34;请帮忙！！！

John Smith 80 90 85.0 瑞安布朗80 60 70.0 安娜迈尔斯95 85 90.0

Answer 1

您应该使用上下文管理器打开文件 - 请注意您不需要显式关闭它。

with open("Students_1.txt" , 'w') as input_file:
    input_file.write("John Smith 80 90\n")
    input_file.write("Ryan Brown 80 60\n")
    input_file.write("Anna Myers 95 85\n")

您可以在一行中打开输入文件和输出文件，例如

with open("Students_1.txt" , 'r') as input_file, open("Students_2.txt" , 'w') as output_file:
    for line in input_file:
        y = line.split()
        first_name = y[0]
        last_name = y[1]
        math_grade = parse_to_number(y[2])
        chem_grade = parse_to_number(y[3])
        ave = (math_grade + chem_grade) / 2.0
        print(*y, ave, file=output_file)

将路径存储在变量中是个好主意。还要将代码分解为某些函数。

在找到学生之间的平均成绩后，如何将平均分数追加到列表末尾然后将其转换回字符串？

1 个答案: