我在OCaml中有一个模块,由另一个模块参数化,它代表一个数据结构(H = Hashtable,M = Map,L = LossyMap)。我现在想通过命令行选择这个数据结构。
我创建主处理模块的方式是:
module HashSampler = MakeSampler(HashtableMatrix)
module MapSampler = MakeSampler(MapMatrix)
etc.
不幸的是,在这些代码之间进行多路复用的代码很难看:
match representation with
| "Hashtable" ->
let matrix = HashSampler.create () in
HashSampler.process_file matrix file
| "Map" ->
let matrix = MapSampler.create () in
MapSampler.process_file matrix file
是否有更好的方法可以防止代码重复?
答案 0 :(得分:5)
您可以使用第一类模块。这是一些显示一种可能性的示例代码。
module type Sampler = sig
type t
val create : unit -> t
val process_file : t -> string -> unit
end
module HashSampler : Sampler = struct
type t = unit
let create () = ()
let process_file () file = ()
end
module MapSampler : Sampler = struct
type t = unit
let create () = ()
let process_file () file = ()
end
let choose_sampler : string -> (module Sampler) = function
| "Hashtable" -> (module HashSampler)
| "Map" -> (module MapSampler)
let process representation file =
let (module M) = choose_sampler representation in
let matrix = M.create () in M.process_file matrix file