将自定义类型数组插入postgres

时间:2017-12-03 18:01:02

标签: postgresql go pq

我正在尝试插入一个列,该列是一个自定义类型的数组(ingredient)。我的表是:

CREATE TYPE ingredient AS (
    name text,
    quantity text,
    unit text
);

CREATE TABLE IF NOT EXISTS recipes (
    recipe_id uuid PRIMARY KEY DEFAULT gen_random_uuid(),
    name text,
    ingredients ingredient[],
    // ...
);

使用原始sql,我可以通过以下方式插入一行:

INSERT INTO recipes (name, ingredients) VALUES ('some_name', ARRAY[ROW('aa', 'bb', 'cc'), ROW('xx', 'yy', 'zz')]::ingredient[] );

但是我在努力与pq lib一起努力。我创建了一个pq.Array界面:

type Ingredient struct {
    Name string
    Quantity string
    Unit string
}

type Ingredients []*Ingredient

func (ings *Ingredients) ConvertValue(v interface{}) (driver.Value, error) {
    return "something", nil
}
func (ings *Ingredients) Value() (driver.Value, error) {
    val := `ARRAY[]`
    for i, ing := range ings {
        if i != 0 {
            val += ","
        }
        val += fmt.Printf(`ROW('%v','%v','%v')`, ing.Name, ing.Quantity, ing.Unit)
    }
    val += `::ingredient[]`
    return val, nil
}


// and then trying to insert via:
stmt := `INSERT INTO recipes (
        name,
        ingredients
    )
    VALUES ($1, $2)
`
_, err := db.Exec(stmt,
    "some_name",
    &Ingredients{
        &Ingredient{"flour", "3", "cups"},
    },
)

但是pg不断抛出错误:

  Error insertingpq: malformed array literal: "ARRAY[ROW('flour','3','cups')]::ingredient[]"

我是否回复了错误的driver.Value

2 个答案:

答案 0 :(得分:1)

您可以使用此处列出的方法:https://github.com/lib/pq/issues/544

type Ingredient struct {
    Name string
    Quantity string
    Unit string
}

func (i *Ingredient) Value() (driver.Value, error) {
    return fmt.Sprintf("('%s','%s','%s')", i.Name, i.Quantity, i.Unit), nil
}

stmt := `INSERT INTO recipes (name, ingredients) VALUES ($1, $2::ingredient[])`

db.Exec(stmt, "some_name", pq.Array([]*Ingredient{{"flour", "3", "cups"}}))

或者,如果您在表中有记录并且查询它,您可能会在其 literal 形式中看到成分数组,您可以在插入过程中模仿它。

func (ings *Ingredients) Value() (driver.Value, error) {
    val := `{`
    for i, ing := range ings {
        if i != 0 {
            val += ","
        }
        val += fmt.Sprintf(`"('%s','%s','%s')"`, ing.Name, ing.Quantity, ing.Unit)
    }
    val += `}`
    return val, nil
}

// e.g. `{"('flour','3','cups')"}`

stmt := `INSERT INTO recipes (name, ingredients) VALUES ($1, $2::ingredient[])`

// ...

答案 1 :(得分:0)

您的数据库设计似乎非常复杂,没有考虑SQL的优势(和弱点)。

我建议您将食材分成自己的食谱,并参考食谱。然后找出一个完整的食谱是JOIN操作。

创建数据库:

CREATE TABLE ingredients (
    recipe_id uuid,
    name text,
    quantity int,
    unit text
);

CREATE TABLE recipes (
    recipe_id uuid PRIMARY KEY,
    name text
);

插入食谱并查询以将其读出:

INSERT INTO recipes VALUES (
  '5d1cb631-37bd-46cc-a278-4c8558ed8964', 'cake1'
);

INSERT INTO ingredients (recipe_id, name, quantity, unit) VALUES
  ('5d1cb631-37bd-46cc-a278-4c8558ed8964', 'flour', 3, 'cups'),
  ('5d1cb631-37bd-46cc-a278-4c8558ed8964', 'water', 1, 'cups')
;

SELECT r.name, i.name, i.quantity, i.unit
FROM ingredients AS i
INNER JOIN recipes AS r
ON r.recipe_id=i.recipe_id;

SQLFiddle链接:http://sqlfiddle.com/#!17/262ad/14