我正在尝试插入一个列,该列是一个自定义类型的数组(ingredient
)。我的表是:
CREATE TYPE ingredient AS (
name text,
quantity text,
unit text
);
CREATE TABLE IF NOT EXISTS recipes (
recipe_id uuid PRIMARY KEY DEFAULT gen_random_uuid(),
name text,
ingredients ingredient[],
// ...
);
使用原始sql,我可以通过以下方式插入一行:
INSERT INTO recipes (name, ingredients) VALUES ('some_name', ARRAY[ROW('aa', 'bb', 'cc'), ROW('xx', 'yy', 'zz')]::ingredient[] );
但是我在努力与pq
lib一起努力。我创建了一个pq.Array
界面:
type Ingredient struct {
Name string
Quantity string
Unit string
}
type Ingredients []*Ingredient
func (ings *Ingredients) ConvertValue(v interface{}) (driver.Value, error) {
return "something", nil
}
func (ings *Ingredients) Value() (driver.Value, error) {
val := `ARRAY[]`
for i, ing := range ings {
if i != 0 {
val += ","
}
val += fmt.Printf(`ROW('%v','%v','%v')`, ing.Name, ing.Quantity, ing.Unit)
}
val += `::ingredient[]`
return val, nil
}
// and then trying to insert via:
stmt := `INSERT INTO recipes (
name,
ingredients
)
VALUES ($1, $2)
`
_, err := db.Exec(stmt,
"some_name",
&Ingredients{
&Ingredient{"flour", "3", "cups"},
},
)
但是pg不断抛出错误:
Error insertingpq: malformed array literal: "ARRAY[ROW('flour','3','cups')]::ingredient[]"
我是否回复了错误的driver.Value
?
答案 0 :(得分:1)
您可以使用此处列出的方法:https://github.com/lib/pq/issues/544
type Ingredient struct {
Name string
Quantity string
Unit string
}
func (i *Ingredient) Value() (driver.Value, error) {
return fmt.Sprintf("('%s','%s','%s')", i.Name, i.Quantity, i.Unit), nil
}
stmt := `INSERT INTO recipes (name, ingredients) VALUES ($1, $2::ingredient[])`
db.Exec(stmt, "some_name", pq.Array([]*Ingredient{{"flour", "3", "cups"}}))
或者,如果您在表中有记录并且查询它,您可能会在其 literal 形式中看到成分数组,您可以在插入过程中模仿它。
func (ings *Ingredients) Value() (driver.Value, error) {
val := `{`
for i, ing := range ings {
if i != 0 {
val += ","
}
val += fmt.Sprintf(`"('%s','%s','%s')"`, ing.Name, ing.Quantity, ing.Unit)
}
val += `}`
return val, nil
}
// e.g. `{"('flour','3','cups')"}`
stmt := `INSERT INTO recipes (name, ingredients) VALUES ($1, $2::ingredient[])`
// ...
答案 1 :(得分:0)
您的数据库设计似乎非常复杂,没有考虑SQL的优势(和弱点)。
我建议您将食材分成自己的食谱,并参考食谱。然后找出一个完整的食谱是JOIN
操作。
创建数据库:
CREATE TABLE ingredients (
recipe_id uuid,
name text,
quantity int,
unit text
);
CREATE TABLE recipes (
recipe_id uuid PRIMARY KEY,
name text
);
插入食谱并查询以将其读出:
INSERT INTO recipes VALUES (
'5d1cb631-37bd-46cc-a278-4c8558ed8964', 'cake1'
);
INSERT INTO ingredients (recipe_id, name, quantity, unit) VALUES
('5d1cb631-37bd-46cc-a278-4c8558ed8964', 'flour', 3, 'cups'),
('5d1cb631-37bd-46cc-a278-4c8558ed8964', 'water', 1, 'cups')
;
SELECT r.name, i.name, i.quantity, i.unit
FROM ingredients AS i
INNER JOIN recipes AS r
ON r.recipe_id=i.recipe_id;
SQLFiddle链接:http://sqlfiddle.com/#!17/262ad/14