Question

我在.h文件中有以下代码：

@interface ComposeViewController : UIViewController {
    id  delegate;
    IBOutlet UITextField *notificationTitle;
}
@property (nonatomic, assign) id  delegate;
- (IBAction)done:(id)sender;
- (void)scheduleAlert;
@end

并且在.m文件

- (void)scheduleAlert {
        // open an alert with just an OK button
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"UIAlertView" message:(@"Hi") delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
        [alert show];

        [alert release];
}

上我想将NSString *notificationTitle的内容放在*alert的消息支持上。如果我使用该代码，它会崩溃

- (void)scheduleAlert {
        // open an alert with just an OK button
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"UIAlertView" message:(@"%@", notificationTitle)
                               delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
        [alert show];
        [alert release];
}

我如何将*notificationTitle传递给*alert消息？

提前谢谢你：）

Answer 1

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"UIAlertView" 
                          message:notificationTitle
                          delegate:self 
                          cancelButtonTitle:@"OK" 
                          otherButtonTitles: nil];

或

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"UIAlertView" 
                          message:[NSString stringWithFormat:@"This is the string: %@", notificationTitle]
                          delegate:self 
                          cancelButtonTitle:@"OK" 
                          otherButtonTitles: nil];

Answer 2

对于UIText字段，您应该使用其text属性，如此

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"UIAlertView" message:notificationTitle.text delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];

将文本字段的值传递给CocoaTouch上的函数

2 个答案: