Question

我的控制器中有两种方法。第一个叫做uploads，它显示数据库表中的所有记录，如下所示：

 public function uploads()
    {
        //return Upload::all();
        $uploads = Upload::all();
        return view('uploads')->with('uploads',$uploads);
    }

此功能正常，我的视图中已成功检索到所有记录。

问题在于第二种方法upload，其目的是在上传列表中点击其名称时显示单个上传的数据。

目前，我有这个：

 public function upload($id)
{
    return Upload::find($id);
}

我不确定如何完成此功能。

我的观点如下：

 @extends('layouts.app')
@section('content')
    <h1>Uploads</h1>
    @if(count($uploads)>0)
@foreach($uploads as $upload)
    <div class="well">
        <h3><a href="/uploads/{{$upload->id}}">{{$upload->name}}</a> </h3>
        <small>Written on {{$upload->created_at}}</small>
    </div>
        @endforeach
    @else
    <p>No uploads found</p>
    @endif

@endsection

我不确定要放入web.php的内容，所以我的路线看起来像这样：

    Route::get('/uploads', function () {
    return view('uploads');
});

Auth::routes();
Route::get('/uploads','UploadController@uploads')->name('uploads');

有人能帮助我做这项工作吗？我只想在点击上传的名称时看到关联数组与数据库中的记录。在路线和我看来，我需要添加什么？

Answer 1

// Controller
public function uploads()
{
    $uploads = Upload::all();
    return view('uploads')->with('uploads', $uploads);
}

您可以在此处使用Laravels IOC容器，让Laravel在您的控制器操作中传递正确的上传。

public function showUploadDetail(Upload $upload)
{
    return view('uploadDetail')->with('upload', $upload);
}

使用示例内容创建名为uploadDetail.blade.php的新刀片文件：

@extends('layouts.app')

@section('content')
   <h1>Upload Detail</h1>
   <p>ID: {{ $upload->id }}</p>
@endsection

正如fil已经提到的那样，调整您的路线：

Route::get('/upload/{id}', 'UploadController@upload')->name('upload');

Answer 2

好的尝试这样的事情

public function upload($id)
{ 
  $uploads = Upload::find($id);

  return view('uploads')
    ->with('uploads', $uploads);
}

并在你的刀片中

@extends('layouts.app')

@section('content')
   <h1>Uploads</h1>
   @if(is_array($uploads) and count($uploads) > 0)
      @foreach($uploads as $upload)
        <div class="well">
          <h3><a href="/upload/{{$upload->id}}">{{$upload->name}}</a> </h3>
          <small>Written on {{$upload->created_at}}</small>
        </div>
      @endforeach
   @else
     <div class="well">
       <h3><a href="/uploads/{{$uploads->id}}">{{$uploads->name}}</a> </h3>
       <small>Written on {{$uploads->created_at}}</small>
     </div>
   @endif

@endsection

在你的路线

Route::get('/upload/{id}', 'UploadController@upload')->name('upload');

或者您可以创建一个单独的刀片，对于单个视图，说刀片的名称是upload.blade.php而不是uploads.blade.php，以便在文件名和目的方面更加清晰。

Answer 3

您没有在web.php中指定显示单个记录的路由。

Web.php

所以，只需将以下路线添加到您的web.php

即可

Route::get('/uploads/{upload_id}','UploadController@upload')->name('single.upload');

使用UploadController中的以下功能更改上传功能： 此函数检索上载记录并将该记录返回到视图：

控制器

public function upload($upload_id)
{
    $upload= Upload::find($upload_id);
    //var_dump($upload);   //Un-comment this line to show full Returned Data
    return view('view_upload',compact('upload'));
}

创建名为view_upload.blade.php的刀片文件，以显示所选的单个上传内容。

@extends('layouts.app')

@section('content')
   <h1>Upload Detail</h1>
   <p>ID: {{ $upload->id }}</p>
   //Following Line Display all the Record.
   // var_dump($upload);
@endsection

在laravel中从数据库中检索和显示单个记录

3 个答案: