我目前正在制作一个吸引力的代码,我的概念是将细胞分配给人口,绿色空间和居住空间等因素。我想编码这些因素之间的吸引力关系,其中人口被绿色空间和居住空间吸引到绿色空间。我有几个C#组件,但由于此序列包含无元素错误,其中一些组件无法正常工作。我似乎无法在代码中找到错误,如果有人知道如何解决这个问题,我将不胜感激。谢谢你的帮助!
//======================================================
// ------- compute the attractivity landscape ----------
//======================================================
// -- find the max distance value - usually the diagonal from first to last:
int nrLocations = Distances.BranchCount;
int nrDists = Distances.Branch(0).Count;
double maxDist = Distances.Branch(0)[nrDists - 1];
// -- the list store the attractivity values for population to green spaces and housing to green spaces
List<double> attractPop = new List<double>();
List<double> attractSpaces = new List<double>();
List<double> attractResid = new List<double>();
double maxPop = PopulDistrib.Max();
double maxSpaces = GreenSDistrib.Max();
double maxResid = ResiDistrib.Max();
for(int i = 0; i < nrLocations; i++)
{
// -- reset lists in each loop:
double curPopAttract = 0;
double curSpacesAttract = 0;
double curResidAttract = 0;
for(int k = 0; k < nrDists; k++)
{
double curPop = PopulDistrib[k] / maxPop; // population of all cells
double curSpaces = GreenSDistrib[k] / maxPop; // Green Spaces of all cells
double curResid = ResiDistrib[k] / maxResid; // Residential Spaces of all cells
// -- distances to all cells:
// -- index i = from current cell // index k = to other cells
// -- division by maxDist gives normalized values in the range [0; 1] for the distance
double curDist = Distances.Branch(i)[k] / maxDist;
// ** Remember: the distances are normalized! Therefore:
// ** (1 - distance) :: makes close things more important than distant ones.
// ** (Math.Pow(1-distance, 6); :: decrease the effect of the distance exponentially.
// ** The perception of people concerning things in a certain distance can now be expressed by:
double distPerceptPop = Math.Pow(1 - curDist, 7);
//Print("distPercept: " + distPerceptPop.ToString());
// -- in addition, we just cut the relevance of distant things completely:
if (distPerceptPop < 0.4) distPerceptPop = 0;
// -- corresponding "perception" of Green Spaces concerning things in a distance:
double distPerceptSpaces = Math.Pow(1 - curDist, 2);
// -- corresponding "perception" of Residential Space concerning things in a distance:
double distPerceptResid = Math.Pow(1 - curDist, 4);
// ----------- Attractivity Functions ----------------------
// -- define the functions for the attractivity ------------
// -- here we control, what is prefered by which land use --
// -- linear attractivity function -> can become more complex functions!!!
// -- people like to be close to Green Spaces:
curPopAttract += ((distPerceptPop) * curSpaces );
//double curAttract = ((distPerceptPop) * curPop );
//curPopAttract += curAttract;
//Print("attractivityPop: " + curPopAttract.ToString());
// -- people DON'T like to be close to other people:
//curPopAttract += 1- ((distPerceptPop) * curPop );
// -- people DON'T like to be close to other people, + but to workplaces:
//double weightImportWork = 0.3; // -- weighting factor to express the importancy to be close to workplaces in contrast to be away from other people
//curPopAttract += 1- ((distPerceptPop) * curPop ) + weightImportWork * Math.Pow(1 - curDist, 2) * curWork;
// -- Residential Spaces like to be close to Green Spaces
curResidAttract += (distPerceptResid) * curSpaces;
// *** EXPERIMENT WITH THE ATTRACTIVITY FUNCTIONS ABOVE !!! **********************************
// *** You may also add additional relations similar to the other system dynamics examples ***
}
// -- collect the current values in the attractivity values lists:
attractPop.Add(curPopAttract);
attractSpaces.Add(curSpacesAttract);
attractResid.Add(curResidAttract);
}
//=======================================================
// -- normalize the attractivity values for both lists --
double minPopAtt = attractPop.Min();
double maxPopAtt = attractPop.Max();
double minSpacesAtt = attractSpaces.Min();
double maxSpacesAtt = attractSpaces.Max();
double minResidAtt = attractResid.Min();
double maxResidAtt = attractResid.Max();
// -- formula for normalization to the range [0; 1]:
// -- normalized valueOfList = (valueOfList - minValueOfList) * 1 / maxValueOfList
for(int i = 0; i < attractPop.Count; i++)
{
attractPop[i] = (attractPop[i] - minPopAtt) * (1 / maxPopAtt);
attractSpaces[i] = (attractSpaces[i] - minSpacesAtt) * (1 / maxSpacesAtt);
attractResid[i] = (attractResid[i] - minResidAtt) * (1 / maxResidAtt);
}
//=======================================================
// -- return the lists:
AttractPop = attractPop;
AttractSpaces = attractSpaces;
AttractResid = attractResid;
答案 0 :(得分:0)
您正在空集合上调用.Max()
或.Min()
。
检查空集合,例如使用if (!collection.Any()) ...
,然后中止(如果这是一个输入错误),或调整算法以解释它。
答案 1 :(得分:0)
正如彼得所说,你在空集合上呼叫Min()
和Max()
。
解决方法是:
double minPopAtt = attractPop.DefaultIfEmpty(-1).Min();
如果您的收藏是空的,-1将是您的默认值。