Question

大家好我试图在表单中附加表格。但是我在控制台中有一条错误消息："Uncaught SyntaxError: missing ) after argument list"。当我单击按钮添加行时，它会一直指向我的PHP脚本。我试图解决这个问题，但无论如何对不起英语不好，这就是代码。

＆＃13;

$('#more_row').append('<tr id="row'+i+'"><td><?php echo "<select name='alpha_num[]' class='form-control' id='item'>"; echo"<option value=''selected disabled>Select Material</option>";while($row = mysqli_fetch_row($result1)){echo"<option value=$row[0]>$row[1]$row[0]</option>";}echo"</select>";?></td><td><input type="text" name="qty[]" class="form-control" id="quantity" placeholder="Qty"></td><td><input type="text" name="uom[]" class="form-control" id="um" placeholder="UOM"></td><td><select name="status[]" class="form-control" id="stat"><option value="approved">approved</option><option value="return">return</option></select></td><td><button id="'+i+'" class="btn btn-danger btn_remove">X</button></td></tr>');
});

$(document).on('click', '.btn_remove', function(){  
  var button_id = $(this).attr("id");   
  $('#row'+button_id+'').remove();  
});

＆＃13;

<div class="panel-body">
  <form method="post" action="material_receive_report_process.php">
    <div class="row">
      <div class="col">
        <label for="dr">PO.NO</label>
        <input type="text" name="dr_no" class="form-control" id="dr">
      </div>

      <div class="col">
        <label for="dr">DR.NO</label>
        <input type="text" name="dr_no" class="form-control" id="dr">
      </div>

      <div class="col">
        <label for="date">Date</label>
        <input type="text" name="date" class="form-control" id="date">
      </div>  
    </div>

    <table id="more_row">
      <tr>
        <td>
          <?php echo "<select name='alpha_num[]' class='form-control' id='item'>"; 
            echo"<option value=''selected disabled>Select Material</option>";
            while($row = mysqli_fetch_row($result1)){   
              echo"<option value=$row[0]>$row[1]$row[0]</option>";
            }
            echo"</select>";
          ?>
        </td>
        <td>
          <input type="text" name="qty[]" class="form-control" id="quantity" placeholder="Qty">
        </td>
        <td>
          <input type="text" name="uom[]" class="form-control" id="um" placeholder="UOM">
        </td>
        <td>
          <select name="status[]" class="form-control" id="stat">
            <option value="approved">approved</option>
            <option value="return">return</option>
          </select>
        </td>
        <td><button id="add1" class="btn btn-info">Add</button></td>
      </tr>
    </table>
    <br>
    <p>Condition:
      <input type="checkbox" name="condition[]" value="damage_visible">Damage visible
      <input type="checkbox" name="condition[]" value="good_condition">Good conditon
      <input type="checkbox" name="condition[]" value="full_qty">Full qty
      <input type="checkbox" name="condition[]" value="partial_qty">Partial qty</p>

      <div class="form-group">
        <label for="supp">Supplier</label>
        <input type="text" name="supplier" class="form-control" id="supp">
      </div>

      <div class="form-group">
        <label for="remark">Remarks</label>
        <textarea name="remark" class="form-control" id="remark"></textarea></p>
        <input type="submit" name="save" class="btn btn-success" value="Save">
      </div>
    </form>
    <br><br>
  </div>
</div>

＆＃13;

Answer 1

＆＃39;添加行＆＃39;按钮提交表单，因为the default value for the type attribute of button elements is "submit"。我的猜测是语法错误是由于PHP在Javascript中转储的单引号，双引号和换行符的混乱。查看浏览器生成的代码。这是需要正确形成的东西。

Answer 2

错误很可能是由于Php和JavaScript字符串之间的冲突造成的。考虑转义ie'和使用不同的两个说JavaScript使用双引号“而Php使用单引号'

使用jQuery与php追加表

2 个答案: