Question

大家好，所以我正在创建一个学生成绩菜单，我想输入学生姓名和两个使用泡菜的测验成绩。输入这些成绩后，我想创建一个报告，在我尝试为我的菜单选项2搜索单个学生后，向所有学生显示菜单选项3，但每次我尝试打印时都会收到错误代码它。

import pickle

def menu():
  selection = input("0\tExit"
                  "\n1\tEnter Student Name/Grades"
                  "\n2\tIndividual Report"
                  "\n3\tReports"
                  "\nEnter Menu Number: ")
  if selection == "0":
    systemExit()
  if selection == "1":
    studentData()
  if selection == "2":
    singleReport()
  if selection == "3":
    studentReports()

def systemExit():
  exit()

def studentData():
  name = input("Enter Student Name: ")
  quiz1 = input("Enter Quiz 1: ")
  quiz2 = input("Enter Quiz 2: ")

with open("pStudent_Quiz_Grades.p", "ab") as pFile:
    pickle.dump((name, (quiz1, quiz2)), pFile)
clearScreen()
return()

def clearScreen():
  print("\n" * 5)
  return ()

def singleReport():
  pFile = open("pStudent_Quiz_Grades.p", "rb")
  grades_dict = pickle.load(pFile)

  search = input("Enter a Name to Search: ")

  for name in grades_dict:
    if name.upper() == search.upper():
        print(name+": "+str("pStudent_Quiz_Grades.p"[name]))

def studentReports():
  pFile = pickle.load(open("pStudent_Quiz_Grades.p", "rb"))
  print(pFile)

while True:
  menu()

Answer 1

我的答案仅基于我给出的错误，其内容如下：

Traceback (most recent call last): File "D:/PyCharm Projects/Fundamentals of Programming/StuGrades HW.py", line 57, in <module> menu() File "D:/PyCharm Projects/Fundamentals of Programming/StuGrades HW.py", line 21, in menu singleReport() File "D:/PyCharm Projects/Fundamentals of Programming/StuGrades HW.py", line 49, in singleReport if name.upper() == search.upper(): AttributeError: 'tuple' object has no attribute 'upper'

该错误声明该名称是一个元组，它不能使用方法上限而且只有字符串允许此方法。因此，我建议使用print进行简单的调试，您可以执行以下操作：

for name in grades_dict:
print "name", name "and type is", type(name)
if name.upper() == search.upper():
    print(name+": "+str("pStudent_Quiz_Grades.p"[name]))

使用此打印语句，您可以检查名称的外观以及数据名称的类型，显然应该是一个元组。此外，如果我们假设搜索是字符串变量，则无法将字符串与元组进行比较。所以我建议你在调试之后将名称转换为字符串，这样你就可以让程序比较搜索是否为字符串。

尝试为个人和所有学生加载学生成绩菜单的错误代码

1 个答案: