我正在尝试自学PHP。我想知道如何与数据库交互并从网站插入数据，并将数据显示回网页上的表格。
我试图让用户编辑结果或将它们显示在输入框中。这样，用户可以编辑数据并将其发送回数据库。但是，我被困住了。我尝试过不同的方法，似乎没有一种方法可行。我接受了建议。
bookingid是用户选择的内容。
我知道所有的表名都不是那么好，但我正在学习。
$query = "SELECT * FROM Trip_Booked Where bookingId = $bookingid";
//executes the query
$result = mysqli_query($db,$query);
// create table and display top row
echo "<td>".$row['email']."</td>";
echo "<div align='center'>";
echo "<table cellpadding=2 border=1>";
echo "<tr>";
echo "<td><strong>booking ID</strong></td>";
echo "<td><strong>boatdate</strong></td>";
echo "<td><strong>fromdate</strong></td>";
echo "<td><strong>saleto</strong></td>";
echo "<td><strong>salefrom</strong></td>";
echo "<td><strong>NoOfAdults</strong></td>";
echo "<td><strong>NoOfWheelchair</strong></td>";
echo "<td><strong>NoUnder2</strong></td>";
echo "<td><strong>NoChild3–10</strong></td>";
echo "<td><strong>NoChild11–16</strong></td>";
echo "<td><strong>TotalPassgers</strong></td>";
echo "</tr>";
// print each record one after another
while($row = mysqli_fetch_assoc($result))
{
echo "<tr>";
echo "<td>".$row['bookingId']."</td>";
echo "<td>".$row['boatDate']."</td>";
echo "<td>".$row['fromDate']."</td>";
echo "<td>".$row['saleto']."</td>";
echo "<td>".$row['salefrom']."</td>";
echo "<td>".$row['NoOfAdults']."</td>";
echo "<td>".$row['NoOfWheelchair']."</td>";
echo "<td>".$row['NoUnder2']."</td>";
echo "<td>".$row['NoChild3–10']."</td>";
echo "<td>".$row['NoChild11–16']."</td>";
echo "<td>".$row['TotalPassgers']."</td>";
echo "</tr>";
}
echo "</table>";
echo "</div>";
?>
我希望结果显示在一个输入框中供用户编辑，因为它将进入表格并检查它是否从数据库中提取正确的信息。
答案 0 :(得分：0)
您需要将数据输出到所需的输入字段中。小例子：
<input type="hidden" name="bookingId" value="<?php echo $row["bookingId"];?>" />
<input type="text" name="NoOfAdults" value="<?php echo $row["NoOfAdults"];?>" />
使用POST的表单操作，然后您可以使用$_POST['NoOfAdults']运行UPDATE查询并使用$_POST['bookingId']作为WHERE
答案 1 :(得分：0)
一个非常简单的例子;仔细查看mysqli的用法，因为我不使用mysqli ...
需要注意的事项：
GET还是POST。我同时使用GET和POST的原因是因为我使用GET来显示特定记录;但POST用于更改记录的任何内容。<?= ?>格式是个人偏好;我喜欢它，因为它使HTML代码更清晰，并使PHP尽可能不引人注目。<form method='{GET | POST}'>而不使用action只需发送回相同的网址即可。
// Create connection
$db = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($db->connect_error) {
die("Connection failed: " . $db->connect_error);
}
// first, take action on POST results if this is an update
if($_POST['action']=='update') {
// use prepared query to avoid SQL injection
$query = "UPDATE Trip_Booked SET boatDate=?, fromDate=?, saleto=?, salefrom=?, NoOfAdults=?, NoOfWheelchair=?, NoUnder2=?, NoChild3_10=?, NoChild11_16=?, TotalPassgers=? WHERE bookingId=?";
$result = $db->prepare($query);
$result->bind_param("ssssiiiiiii", $_POST['boatDate'],$_POST_['fromDate'],$_POST_['saleto'],$_POST_['salefrom'],$_POST_['NoOfAdults'],$_POST_['NoOfWheelchair'],$_POST_['NoUnder2'],$_POST_['NoChild3_10'],$_POST_['NoChild11_16'],$_POST_['TotalPassgers'],$_POST['bookingId']);
$result->execute();
// since we don't want post data resent on back button press, redirect back to this page (change url to match)
header("Location: http://www.example.com/?bookingId=" . $POST['bookingId']);
exit;
}
// if not an update, but we do have the booking ID, find the row using BookingId
// use prepared query to avoid SQL injection
if($_GET['bookingId']) {
$query = "SELECT * FROM Trip_Booked Where bookingId = ?";
$result = $db->prepare($query);
$result->bind_param("s", $_GET['bookingId']);
$result->execute();
}
现在，我们拥有输出HTML所需的一切。请记住，PHP是一种模板化语言，所以不要害怕使用它。
<!-- language: lang-html -->
// continuing from above
?><html>
<head>
<title>Edit a Booking</title>
</head>
<body>
<h1>Choose a Page</h1>
<form method="get">
<label for="bookingid">Page</label><input type="text" id="bookingid" name="bookingId" />
<input type="submit" value="Go to page" />
</form>
<?php if($_GET['bookingId']): ?>
<!-- better way to enter values: -->
<!-- <div><label for="fieldname">Label</label><input type="text" id="fieldname" name="fieldname" value="{value}" /></div> -->
<h1>Edit Fields</h1>
<form method="post">
<input type="hidden" name="action" value="update" />
<input type="hidden" name="bookingId" value="<?= htmlentities($_GET['bookingId']) ?>" />
<table>
<thead>
<tr>
<th>bookingId</th>
<th>boatDate</th>
<th>fromDate</th>
<th>saleto</th>
<th>salefrom</th>
<th>NoOfAdults</th>
<th>NoOfWheelchair</th>
<th>NoUnder2</th>
<th>NoChild3_10</th>
<th>NoChild11_16</th>
<th>TotalPassgers</th>
</tr>
</thead>
<tbody>
<!-- since this is an edit of only one record, you could use 'if' instead of 'while' -->
<?php while($row = $result->fetch_object())): ?>
<tr>
<th><input type="text" name="bookingId" value="<?= $row->bookingId ?>" /></th>
<th><input type="text" name="boatDate" value="<?= $row->boatDate ?>" /></th>
<th><input type="text" name="fromDate" value="<?= $row->fromDate ?>" /></th>
<th><input type="text" name="saleto" value="<?= $row->saleto ?>" /></th>
<th><input type="text" name="salefrom" value="<?= $row->salefrom ?>" /></th>
<th><input type="text" name="NoOfAdults" value="<?= $row->NoOfAdults ?>" /></th>
<th><input type="text" name="NoOfWheelchair" value="<?= $row->NoOfWheelchair ?>" /></th>
<th><input type="text" name="NoUnder2" value="<?= $row->NoUnder2 ?>" /></th>
<th><input type="text" name="NoChild3_10" value="<?= $row->NoChild3_10 ?>" /></th>
<th><input type="text" name="NoChild11_16" value="<?= $row->NoChild11_16 ?>" /></th>
<th><input type="text" name="TotalPassgers" value="<?= $row->TotalPassgers ?>" /></th>
</tr>
<?php endwhile; ?>
</tbody>
</table>
<input type="submit" value="Edit" />
</form>
<?php endif; ?>
</body>
</html>