Question

我一直在努力创建一个程序，将21张卡分成3堆。然后要求用户考虑卡并告诉程序哪个堆是他们的卡。此步骤重复4次，直到卡片正好位于21张卡片的中间。该程序应该转到用于打印用户卡的end()函数，问题是，一切正常，但它会在end()函数中打印语句5次。我知道它可能是非常愚蠢的东西，但我想不出解决方案。提前谢谢。

import random

cards = []
count = 0

def end():
    print("Your card is: ", cards[10])

def split():
    def choice():
        global count
        while True:
            if count >=0 and count <= 3:
                global cards
                user = input("Think of a card. Now to which pile does your card belong to?: ")
                count = count + 1
                if user == "1":
                    del cards[:]
                    cards = (pile_2 + pile_1 + pile_3)
                    print(cards)
                    split()
                elif user == "2":
                    del cards[:]
                    cards = (pile_1 + pile_2 + pile_3)
                    print(cards)
                    split()
                elif user == "3":
                    del cards[:]
                    cards = (pile_1 + pile_3 + pile_2)
                    print(cards)
                    split()
                else:
                    print("Invalid input")
                    main()
            elif count == 4:
                end()
                break

    pile_1 = []
    pile_2 = []
    pile_3 = []
    counter = 0
    sub_counter = 0

    while True:
        if sub_counter >= 0 and sub_counter <= 20:
            for item in cards:
                if counter == 0:
                    pile_1.append(item)
                    counter = counter + 1
                elif counter == 1:
                    pile_2.append(item)
                    counter = counter + 1
                elif counter == 2:
                    pile_3.append(item)
                    counter = 0

                sub_counter = sub_counter + 1
        elif sub_counter == 21:
            False
            break
    print()
    print("first pile: ", pile_1)
    print("second pile: ", pile_2)
    print("third pile: ", pile_3)
    choice()

def main():
    file = open('cards.txt.', 'r')
    for line in file:
        cards.append(line)
    file.close
    random.shuffle(cards)
    print(cards)
    split()

main()

Answer 1

你有递归电话。 split（）调用choose（）然后再次调用split（），这可以调用main（）再调用split（）。

Answer 2

当你到达elif count == 4行时，count总是为4.这就是原因。如果你改变顺序，我可以预感它可以工作：

...
if count == 4:
    end()
    break
elif count >= 0 and count <=3:
    ...

但是，如果你可以在没有全局变量的情况下编写它，那就更好了。您可以使用本地变量而不是全局变量作为参数传递给下一个函数。像这样：

import random

def end(cards):
    print("Your card is: ", cards[10])

def choice(count,pile_1,pile_2,pile_3):
    while True:
        user = input("Think of a card. Now to which pile does your card belong to?: ")
        if user == "1": 
            cards = (pile_2 + pile_1 + pile_3) 
            print(cards)
            split(count+1, cards)
            break
        elif user == "2": 
            cards = (pile_1 + pile_2 + pile_3) 
            print(cards)
            split(count+1, cards)
            break
        elif user == "3": 
            cards = (pile_1 + pile_3 + pile_2) 
            print(cards)
            split(count+1, cards)
            break
        else:
            print("Invalid input")

def split(count,cards):
    if count == 4:
        end(cards)
        return
    pile_1 = []
    pile_2 = []
    pile_3 = []
    for i in range(0,21,3):
        pile_1.append(cards[i])
        pile_2.append(cards[i+1])
        pile_3.append(cards[i+2])
    print()
    print("first pile: ", pile_1)
    print("second pile: ", pile_2)
    print("third pile: ", pile_3)
    choice(count,pile_1,pile_2,pile_3)

def main():
    cards = []
    file = open('cards.txt.', 'r')
    for line in file:
    cards.append(line.strip())
    file.close
    random.shuffle(cards)
    print(cards)
    split(0, cards)

main()

Answer 3

我找到了一个解决方案：

这只是一个身份问题，

而不是：

  elif count == 4:
       end()
       break

我把break语句放在与elif相同的行上：

 elif count == 4:
     end()
 break

似乎解决了它

卡片特技程序

3 个答案: